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2 answers:
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Answer:
E = 2.84 x 10⁵ N/ C
Explanation:
given,
initial speed of electron,u = 2 x 10⁷ m/s
final speed of electron, v = 4 x 10⁷ m/s
distance = 1.2 cm
electric field strength = ?
using equation of motion for acceleration of electron
v² = u² + 2 a s
a = 5 x 10¹⁶ m/s²
now,
Force of electric field is equal to , F = q E
and we also know that F = m a
now,
where q is the charge of electron = 1.6 x 10⁻¹⁹ C
m is mass of electron, m = 9.1 x 10⁻³¹ Kg
so,
E = 2.84 x 10⁵ N/ C
the electric field strength is equal to E = 2.84 x 10⁵ N/ C