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Bumek [7]
2 years ago
12

What does ! mean in a math problem?

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
7 0
Answer:
! is the symbol for factorial.

Reason:
n! is the product (multiplication) of all the numbers from n down to 1, inclusive, i.e. n × (n−1) × (n−2) × … × 2 × 1.

For example:

5! = 5 × 4 × 3 × 2 × 1 = 120

10! = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 3,628,800

OR:
The there was a typo or a mistake that was made in the making of these questions.


Give this answer Brainliest!

Anton [14]2 years ago
5 0

! is shorthand for the factorial function. If n is a non-negative integer, then

n! = n\times(n-1)\times(n-2)\times\cdots3\times2\times1

with 0! = 1.

So how to compute n! ?

Multiply each number in sequence from that number to 1.

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A company mixes two kinds of cleansers to get a blend they sell for 59 cents a liter. One of the cleansers costs 50 cents per li
Lilit [14]

Answer:

Cleanser that costs 50 cents is 1400 liters, Cleanser that costs 80 cents is 600 liters.

Step-by-step explanation:

We can solve this by using <em>simultaneous equations</em>:

  1. Let us express the question in terms of equations

Let a be cleanser at 50 cents and let b be the cleanser at 80 cents.

Equation 1: 0.5a + 0.8b = 0.59(a+b)

Equation 2: a + b = 2000

From equation 2, a = 2000 - b (Let's call this equation 3)

    2. Substituting equations 2 and 3 in Equation 1:

0.5a + 0.8b = 0.59(a+b)

0.5(2000 - b) + 0.8b = 0.59(2000)

1000 - 0.5b + 0.8b = 1180

0.3b = 180

b = 600

Substitute in equation 3:

a = 2000 - 600

a = 1400

As a note, I formed equation 1 because I know for a fact the cost per liter of a and b. I also know it is sold at 0.59 cents per liter. We are selling 2000 liters in this instance, therefore 0.59(2000) = 1180, which in this case is the selling price.

4 0
3 years ago
3/4t-2=5-1/4t<br> slove for t<br> pLeAsEeEe
lukranit [14]

Answer:

no

Step-by-step explanation:

3 0
2 years ago
Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
2 years ago
Read 2 more answers
In january of one winter, 3/10 of a wood pile was used in a wood stove. In February, 2/5 of the wood pile was used. What part of
arsen [322]
2/5 is equivalent to 4/10 so at the end of February 4/10 was used up
And at the end of January, 3/10 was used
so 4/10 + 3/10 = 7/10

At the end of February, 7/10 of the wood was used
6 0
3 years ago
Which of the following numbers is not written in scientific notation?
Sonja [21]

Answer A

Step-by-step explanation:

Because there is a zero at the begining.

8 0
2 years ago
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