Answer:
Step-by-step explanation:
The measure of the floor of the rectangular room that is 12 feet by 15 feet. The formula for determining the area of a rectangle is expressed as
Area = length × width
Area of the rectangular room would be
12 × 15 = 180 feet²
The tiles are square with side lengths 1 1/3 feet. Converting 1 1/3 feet to improper fraction, it becomes 4/3 feet
Area if each tile is
4/3 × 4/3 = 16/9 ft²
The number of tiles needed to cover the entire floor is
180/(16/9) = 180 × 9/16
= 101.25
102 tiles would be needed because the tiles must be whole numbers.
I have no idea what the answer is but add me as a friend
The midpoint between the two points are (0,1/2)
<span>There are equations to calculate the volume of simple geometric objects such as cubes, spheres, cylinders, and cones. Approximate the spacecraft as an assemblage of such objects, calculate the volumes, then add them all up. Example: here.
Create a scale model inside a 3D modeling package, and use the included tools to calculate the internal volume. Example: On my mesh model of the Galactic Cruiser Leif Ericson, the AreaVol script informs me the ship has an internal volumeof 68,784.87 cubic meters.
See if somebody else has already calculated the volume. Example: According to ST-v-SW.Net the internal volume of the TOS Starship Enterprise is 211,248 cubic meters.
Use the known volume of a comparable existing object. Example: a Russian Oscar submarine has a volume of 15,400 cubic meters. It is a good size for a spaceship.
If the spacecraft is approximately a sphere or approximately a cylinder, just use the ship's average radius and height to calculate an approximate volume using the sphere or cylinder volume formulae. Close enough for government work.
Make it up out of your imagination.
Of course there is some differences of opinion on the exact value of the average density of a spacecraft.
One easy figure I've seen in various SF role playing games is a density of 0.1 to 0.2 metric tons per cubic meter (100 to 200 kilograms). That corresponds to average pressure compartments being cubes 10 meters on a side, with pressure bulkheads averaging 17 to 33 kg/m2.
Ken Burnside did some research when he designed his game Attack Vector: Tactical. He found that jet airliners have an average density of about 0.28 metric tons per cubic meter, fighter aircraft 0.35 tons/m3, wet navy warships from 0.5 to 0.6 tons/m3, WWII battleships 0.7 tons/m3 (it don't take much excess mass to send them straight to Davy Jones locker), and submarines 0.9 tons/m3. For the combat spacecraft in AV:T, Ken chose a density of 0.25 tons/m3</span>
Answer:
Radius = 8.575 cm
Step-by-step explanation:
Formula for volume of a pyramid is;
V_p = ½Ah
Where A is area of base and h is height
Also, formula for volume of cone is given as;
V_c = ⅓πr²h
Now, we are told that V_p = V_c and that h is the same for both shapes.
Thus ;
½Ah = ⅓πr²h
h will cancel out to give;
½A = ⅓πr²
Cross multiply to give;
3A/2π = r²
Base area of pyramid is given as 154 cm². Thus;
(3 × 154)/2π = r²
r = √((3 × 154)/2π
r = 8.575 cm
