Luckily for us, the diagram already divided this figure into separate polygons. What I will be explaining is basically the addition of the areas of all the separate polygons. The area of the uppermost triangle is:
1/2 x b x h
= 1/2 x 20 x 8
(the base is 20, because in a parallelogram, opposite sides are congruent)
=10 x 8
= 80 in. squared
The next polygon we will be taking the area of is the parallelogram with the base length of 20 and the height of 16.
Area = b x h
= 20 x 16
= 320 in. squared
Now all we have left to do is add the two areas to obtain the total area.
Total Area = 320 + 80 = 400 in. squared
use the distributive property
combine alike terms
add the negative number to the other side
combine alike terms
then divide on both sides to get the variable by itself
5.25 / .85 you would get 6.17~ but you cant sell 1/4th a cup, so you have to round up, making it 7 cups.
The class midpoint is the lower class limit plus the upper class limit divided by 2 . Add the midpoints column to the original table.
The answer is c and then b and then a
