Answer:
Step-by-step explanation:
a). There are 8 points in the figure attached.
b). There are 9 lines in the given figure.
c). There are 5 planes in the figure attached.
d). Three collinear points are D,G and F.
e). Four co-planar points are G, F, H and C.
f). Intersection of planes ABC and ABE is the common line AB.
g). Intersection of planes BCH and DEF is the common line EF.
h). Intersection of AD and DF is a point D.
Answer:
id say a
Step-by-step explanation:
Answer:
1. Area of rectangular rug is ![110 ft^{2}](https://tex.z-dn.net/?f=110%20ft%5E%7B2%7D)
2. Area of triangular room is ![330ft^{2}](https://tex.z-dn.net/?f=330ft%5E%7B2%7D)
Step-by-step explanation:
This problem bothers on the mensuration of flat shapes, rectangle and triangle.
step one
let us start by solving for the area of the rectangular rug
given data
Area A = ?
Length l = 11 ft
Width w= 10 ft
we know that the area of a rectangle is expressed as
![Area=Length * Width](https://tex.z-dn.net/?f=Area%3DLength%20%2A%20Width)
substituting our given data we have
![Area= 11*10\\Area= 110 ft^{2}](https://tex.z-dn.net/?f=Area%3D%2011%2A10%5C%5CArea%3D%20110%20ft%5E%7B2%7D)
step two
let us solve for the area of the triangular room
given data
Area A = ?
base b = 30 ft
height h= 22 ft
we know that the area of a triangle is expressed as
![Area= \frac{1}{2} *base* height\\](https://tex.z-dn.net/?f=Area%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2Abase%2A%20height%5C%5C)
substituting our given data we have
![Area= \frac{1}{2} * 30* 22\\Area=\frac{660}{2} \\Area= 330 ft^{2}](https://tex.z-dn.net/?f=Area%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%2030%2A%2022%5C%5CArea%3D%5Cfrac%7B660%7D%7B2%7D%20%5C%5CArea%3D%20330%20ft%5E%7B2%7D)
Answer and Step-by-step explanation:
To simplify, distribute the negative number.
-(11 + 2b)
<u>-11 - 2b is the answer.</u>
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<em><u>#teamtrees #PAW (Plant And Water)</u></em>
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<em><u>I hope this helps!</u></em>