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Alecsey [184]
2 years ago
5

Joy read 1/3 of the book in the morning and she reads some more at night by the end of the day she still had 2/5 of the book to

read how much of the book did joy read at night?
Mathematics
1 answer:
larisa [96]2 years ago
4 0

Answer:

4/15

Step-by-step explanation:

Lets find a common denominator in order to find the total amount. There is a common denominator of 15 among 3 and 5. Therefore we will convert the fraction so they have the same denominator.

1/3 > 5/15

2/5 > 6/15

If Joy had read 5/15 of the book before reading at night, she already had the progress of being at 10/15 way through the book. At the end of the day, Joy had only 6/15 left of the book. To find the remainder, we subtract 10-6=4. This helps find the answer that Joy only read 4/15 of the book towards the end of the day.

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Answer:

For the first question the correct form would be B. It would be 6(p-3)=42. For the second question the answer would be 10.

Step-by-step explanation:

For the first question B is correct because it's 3 dollars off which would be -3.

For the second question you would multiply 6 with p and 6 with -3. This would equal to 6p-18. This would make the equation 6p-18=42. You would then add 18 to 42, which equals 60. Finally you would divide 60 by 6, which equals 10, which is your answer.

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A research group at Nike decides to survey NCSU students for their preferences in clothing brands. They divide all students into
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3 years ago
The population at Bishop High School is 2000 students in 2011. Every year the population decreases by 50 students
Artemon [7]

Answer:

  • Let p be the population at t be the number of years since 2011.  Then, p=2000-50t
  • The projected population of the high school in 2015=1800
  • In <u>2019</u> the population be 1600 students

Step-by-step explanation:

Given: The population at Bishop High School students in 2011 =2000

Also,  Every year the population decreases by 50 students which implies the rate of decrease in population is constant.

So, the function is a linear function.

Let p be the population at t be the number of years since 2011.

Then, p=2000-50t

So at t=0, p=2000

In year 2015, t=4, substitute t=4 in the above equation ,we get

p=2000-50(4)\\\Rightarrow\ p=2000-200\\\Rightarrow\ p=1800

Hence, the projected population of the high school in 2015=1800

Now, put p=1600 in the function , we get

1600=2000-50t\\\Rightarrow50t=2000-1600\\\Rightarrow50t=400\\\Rightarrow\ t=\frac{400}{50}\\\Rightarrow\ t=8

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Hence, in <u>2019</u> the population be 1600 students




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3 years ago
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