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4 years ago

See attachment below!!!!

Mathematics

2 answers:

german4 years ago

8 0

Answer:

-6

Step-by-step explanation:

Simplifying it the most gets it to -6

liubo4ka [24]4 years ago

3 0

Answer: Third option.

Step-by-step explanation:

We need to remember these properties:

$log_b(a)^n=nlog_b(a)\\\\log_b(b)=1\\\\\frac{1}{a}=a^{-1}$

Then, given the following expression:

$log_2(\frac{1}{64} )$

You need to:

- Descompose 64 into its prime factors:

$64=2*2*2*2*2*2=2^6$

- Substitute:

$log_2(\frac{1}{2^6} )$

- Apply the properties shown above:

$log_2(2)^{-6}=-6log_2(2)=-6(1)=-6$

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Determine whether the set of vectors <img src="https://tex.z-dn.net/?f=%20v_%7B1%3D%283%2C2%2C1%29%2C%20v_%7B2%7D%20%3D%28-1%2C-

Korolek [52]

Since each vector is a member of $\mathbb R^3$ , the vectors will span $\mathbb R^3$ if they form a basis for $\mathbb R^3$ , which requires that they be linearly independent of one another.

To show this, you have to establish that the only linear combination of the three vectors $c_1\mathbf v_1+c_2\mathbf v_2+c_3\mathbf v_3$ that gives the zero vector $\mathbf0$ occurs for scalars $c_1=c_2=c_3=0$ .

$c_1\begin{bmatrix}3\\2\\1\end{bmatrix}+c_2\begin{bmatrix}-1\\-2\\-4\end{bmatrix}+c_3\begin{bmatrix}1\\1\\-1\end{bmatrix}=(0,0,0)\iff\begin{bmatrix}3&-1&1\\2&-2&1\\1&-4&-1\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix}=\begin{bmatrix}0\\0\\0\end{bmatrix}$

Solving this, you'll find that $c_1=c_2=c_3=0$ , so the vectors are indeed linearly independent, thus forming a basis for $\mathbb R^3$ and therefore they must span $\mathbb R^3$ .

4 0

3 years ago

Solve y = x2 - 18 for x.

Nina [5.8K]

Answer:

Step-by-step explanation:

assuming that x2 = x², then the equation is y= x²-18

y= x²-18

y-18=x²

$\sqrt{y-18}=\sqrt{x^{2} }$

$\sqrt{y-18}= x\\$

so x = $\sqrt{y-18\\}$

7 0

3 years ago

Donna has a $300 loan through the bank she is charged a simple rate The total interest she paid on the loan was $63 As a percent

klasskru [66]

The annual interest rate is 21%

<h3>How to determine the annual interest rate?</h3>

The given parameters are

Loan Amount, P = $300

Interest, I = $63

Number of years, T = 1

The annual interest rate is calculated as

I = PRT

Substitute the known values in the above equation

63 = 300 * R * 1

Evaluate the product

300R = 63

Divide through by 300

R = 21%

Hence, the annual interest rate is 21%

Read more about simple interest at:

brainly.com/question/20690803

#SPJ1

3 0

2 years ago

The domain for f(x) is all real numbers greater than or equal to ___ ?

Shkiper50 [21]

You must set each part of the function equal to zero.

5√(x+2) = x is greater than or equal to -2

So the domain is greater than or equal to -2

7 0

4 years ago

Read 2 more answers

Help me please I am so confused...

Ivahew [28]

Step-by-step explanation:

"b2" was replaced by "b^2". 1 more similar replacement(s).

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

a-((h*(b^2+b^2))/(2))=0

Simplify: hb2 /1

a - hb2 = 0

Factoring: a-hb2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

(A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

AB = BA is the commutative property of multiplication.

- AB + AB equals zero and is therefore eliminated from the expression.

a1 is not a square

Binomial can not be factored as the difference of two perfect squares

a - hb2 = 0

Solve :a-hb2 = 0

I think

6 0

3 years ago