Question

See attachment below!!!!

Answer 1

Answer:

-6

Step-by-step explanation:

Simplifying it the most gets it to -6

Answer 2

Answer: Third option.

Step-by-step explanation:

We need to remember these properties:

$log_b(a)^n=nlog_b(a)\\\\log_b(b)=1\\\\\frac{1}{a}=a^{-1}$

Then, given the following expression:

$log_2(\frac{1}{64} )$

You need to:

- Descompose 64 into its prime factors:

$64=2*2*2*2*2*2=2^6$

- Substitute:

$log_2(\frac{1}{2^6} )$

- Apply the properties shown above:

$log_2(2)^{-6}=-6log_2(2)=-6(1)=-6$