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Mrac [35]
1 year ago
6

Which equation describes how the parent function, y = x cubed, is vertically stretched by a factor of 4?

Mathematics
1 answer:
storchak [24]1 year ago
4 0

The equation that describes how the parent function, y = x³, is vertically stretched by a factor of 4 is y = 4x³.

<h3>We can find how the equation is vertically stretched below:</h3>

When an equation is vertically stretched, it means that the parent equation has been multiplied by a number that is more than one.

This means that the equation is multiplied by some factor.

It is given that we should describe how the parent function is vertically stretched by a factor of 4.

The parent function is given as y = x³.

Since the equation is said to be vertically stretched by a factor of 4, we must multiply the parent equation by 4 to stretch it.

Therefore, we have found the equation that describes how the parent function, y = x³, is vertically stretched by a factor of 4 to be y = 4x³.

Learn more about vertically stretching equations here: brainly.com/question/13671886

#SPJ4

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3 years ago
a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F
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           Find the area, by setting the limits as

               = 4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta

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Therefore;

Mxy=  \int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta

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M= 8\pi dividing it into two volume gives us = 4\pi

means  4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta

             4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)

              c=2\sqrt{2}

       

                 

                 

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3 years ago
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