Answer:
The answer is below
Step-by-step explanation:
The diameter of a tire is 2.5 ft. a. Find the circumference of the tire. b. About how many times will the tire have to rotate to travel 1 mile?
Solution:
a) The circumference of a circle is the perimeter of the circle. The circumference of the circle is the distance around a circle, that is the arc length of the circle. The circumference of a circle is given by:
Circumference = 2π × radius; but diameter = 2 × radius. Hence:
Circumference = π * diameter.
Given that diameter of the tire = 2.5 ft:
Circumference of the tire = π * diameter = 2.5 * π = 7.85 ft
b) since the circumference of the tire is 7.85 ft, it means that 1 revolution of the tire covers a distance of 7.85 ft.
1 mile = 5280 ft
The number of rotation required to cover 1 mile (5280 ft) is:
number of rotation = 
Gropu like terms
(-1/2)x+(3/2)x-4x+3+5=
(2/2)x-4x+8=
1x-4x+8=
-3x+8
Answer:
x=3
Step-by-step explanation:
6x+6/32=9x-9/24
144x+144=288x-288
144x=288x-432
-144x=-432
Therefore, x=3
Answer:
Step-by-step explanation:
From the given attachment to the question, the following can be deduced.
1. M is the midpoint of GH, given that M is the definition of midpoint.
2. GM ≅ MH, given that x = 2. So that,
GM = 5x = 5(2)
= 10
MH = 3x + 4 = 3(2) + 4
= 10
Thus, GM ≅ MH
3. GM = MH is the definition of congruence. This implies that they are similar.
4. 5x = 3x + 4, by substitution property of equality.
Since, x = 2 then;
5(2) = 3(2) + 4
10 - 10
5. 2x = 4, given that x = 2.
6. GH = GM + MH, by division property of equality.