Answer:
okj
Step-by-step explanation:
I don’t understand what you’re saying ?
Answer:
0.14
Step-by-step explanation:
From the question given above, the following data were obtained:
Grade A = 5
Grade B = 10
Grade C = 15
Grade D = 3
Grade F = 2
Sample space (S) = 35
Probability of getting grade A, P(A) =?
The probability that a student obtained a grade of A can be obtained as follow:
Probability of getting grade A, P(A) =
Event of A (nA) / Sample space, (nS)
P(A) = nA/nS
P(A) = 5/35
P(A) = 0.14
Thus, probability that a student obtained a grade of A is 0.14
I think I have the diagram right.
Let ADB = x, and then BDC = x+32.
x+x+32 = 90
2x = 58
x = 29 = ADB
so BDC = 61
The last term is -100 so its either a or d.
Try a:-
(x^2 - 25)(x-2)(x - 2)
= x^2 - 25 (x^2 - 4x + 4)
= x^2 + 4x^3 + 4x^2 - 25x^2 + 100x - 100
= x^4 + 4x^3 - 21x^2 + 100x - 100
Its a.
