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Igoryamba
3 years ago
12

What is 5 + (-8) I need to put it on a number line

Mathematics
2 answers:
Naily [24]3 years ago
8 0

Answer: -3

Step-by-step explanation: 5-8 is -3 so just go 3 to the left from 0 and plug in the point or number

wlad13 [49]3 years ago
7 0

Answer:

5 + (-8)= (-3)

Step-by-step explanation:

If you do keep,change,change you will get

  • 5-8=(-3)

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Frosty Whip Inc. budgets 65 percent of its total expenses for marketing. Total expenses for the company this year are $500,000.
Misha Larkins [42]

65% of the total expenses is for marketing, in which 500,000 is the total.

First, change the percentage into decimal

65% = 65/100 = 0.65

Next, to find the amount budgeted for marketing, multiply the total with the decimal

0.65 x 500000 = 325000

$325000 is used for marketing

hope this helps

6 0
3 years ago
A quarter is what fraction of a dollar
Shkiper50 [21]
Well, a quarter is worth .25 And a dollar is 1.00
So .25 out of 1.00 equals 1/4
Since it takes 4 quarters to make a dollar, and you have 1 quarter.
~Hope this helped
7 0
3 years ago
Read 2 more answers
Analyze the diagram below and complete the instructions that follow.
miv72 [106K]
<h3>Answer:  5/12  (choice C)</h3>

Explanation:

Recall that tangent = opposite/adjacent.

For reference angle M, the side ON = 5 is the opposite side and MN = 12 is the adjacent side. We don't need the hypotenuse.

6 0
3 years ago
3 + (-3)^2 - (9 +7)^0
MatroZZZ [7]

Answer:

11

Step-by-step explanation:

3+(−3)^2−(9+7)^0

=3+9−(9+7)^0

=12−(9+7)^0

=12−16^0

=12−1

=11

any number to the power of 0 is ALWAYS 1

3 0
3 years ago
Read 2 more answers
The level of nitrogen oxides (NOX) in a exhaust of cars of a particular model varies normally with mean 0.25 grams per miles and
antoniya [11.8K]

Answer:

a) 15.87% probability that a single car of this model fails to meet the NOX requirement.

b) 2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

Step-by-step explanation:

We use the normal probability distribution and the central limit theorem to solve this question.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.25, \sigma = 0.05

a. What is the probability that a single car of this model fails to meet the NOX requirement?

Emissions higher than 0.3, which is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.3 - 0.25}{0.05}

Z = 1

Z = 1 has a pvalue of 0.8417.

1 - 0.8413 = 0.1587.

15.87% probability that a single car of this model fails to meet the NOX requirement.

b. A company has 4 cars of this model in its fleet. What is the probability that the average NOX level of these cars are above 0.3 g/mi limit?

Now we have n = 4, s = \frac{0.05}{\sqrt{4}} = 0.025

The probability is 1 subtracted by the pvalue of Z when X = 0.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3 - 0.25}{0.025}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that the average NOX level of these cars are above 0.3 g/mi limit

4 0
3 years ago
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