Please help me with 2 and 3.
2 answers:
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Answer:
slope = 3
Step-by-step explanation:
Calculate the slope m using the slope formula
m =
with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (- 3, - 4)
m = =
= 3
Answer:
The minimum head breadth that will fit the clientele is 4.4 inches.
The maximum head breadth that will fit the clientele is 7.8 inches.
Step-by-step explanation:
Let <em>X</em> = head breadths of men that is considered for the helmets.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.
To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:
It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.
Compute the minimum head breadth that will fit the clientele as follows:
P (X < x) = 0.043
⇒ P (Z < z) = 0.043
The value of <em>z</em> for this probability is:
<em>z</em> = -1.717
*Use a <em>z</em>-table.
Compute the value of <em>x</em> as follows:
Thus, the minimum head breadth that will fit the clientele is 4.4 inches.
Compute the maximum head breadth that will fit the clientele as follows:
P (X > x) = 0.043
⇒ P (Z > z) = 0.043
⇒ P (Z < z) = 1 - 0.043
⇒ P (Z < z) = 0.957
The value of <em>z</em> for this probability is:
<em>z</em> = 1.717
*Use a <em>z</em>-table.
Compute the value of <em>x</em> as follows:
Thus, the maximum head breadth that will fit the clientele is 7.8 inches.
<span>3 cans store
9 tennis balls.
Find the Constant of proportionality and write and equation with regards to this given situation:
=> number of tennis balls = 9
=> number of cans = 3
</span> <span>So the constant of proportionality is in the working column. Pls see attached.<span>
</span></span>
Find the Constant of proportionality and write and equation with regards to this given situation:
=> number of tennis balls = 9
=> number of cans = 3
</span> <span>So the constant of proportionality is in the working column. Pls see attached.<span>
</span></span>