Write 2^40 as an exponent with a base of: a 2^2; b 2^5; c 2^8; 2^10
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The value of x is 3.8
<em><u>Solution:</u></em>
<em><u>Given equation is:</u></em>
We have to solve the equation for "x"
Move the terms so that you end up with only terms involving x on one side of the sign and all the numbers on the other
Therefore, we get
x + 7.4 = 11.2
When we move 7.4 from left side to right side of equation it becomes -7.4
x = 11.2 - 7.4
Subtract 7.4 from 11.2
x = 3.8
Thus value of x is 3.8