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DedPeter [7]
1 year ago
12

Which is the graph of f(x) = }(4)*2

Mathematics
1 answer:
zavuch27 [327]1 year ago
5 0

Answer: D

Step-by-step explanation:

Where the x-intercept is 0.25.

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5/4p=4/3p+3/2 A: The solution set is (_) Simplified B: There is no solution Pick one and if A then simplify the answer
Lady_Fox [76]

Answer:p= -18

Step-by-step explanation:Let's solve your equation step-by-step.

5/4 P= 4/3 P + 3/2

Step 1: Subtract 4/3p from both sides.

5/4 P - 4/3 P = 4/3 P + 3/2 - 4/3 P

-1/12 P = 3/2

Step 2: Multiply both sides by 12/(-1).

(12/-1) × (-1/12 P) = (12/-1) × (3/2)

P = -18

8 0
3 years ago
Read 2 more answers
What are the possible rational zeros of f(x) = x^4 + 6x^3 − 3x^2 + 17x − 15?
loris [4]
Hmm, I got these for roots:
0.7937053103356799
0.026855090968934903   +i* 1.6611004538114105
0.026855090968934903   -i* 1.6611004538114105
-6.84741549227355

8 0
3 years ago
Apakah kesan kedudukan tersebut terhad
Lena [83]

ABB G Ppppwhbbbsbbsbsbsbsjsjkskenennsn

4 0
3 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
Hi what is the four time pi?
Minchanka [31]

Answer:

<h2>12.5663706144 or just 12.57.</h2>

Step-by-step explanation:

4 x pi = 12.57

<h3>Estimate </h3>

Pi is approx. equal to 3.14

4 x 3 = 12

8 0
3 years ago
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