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Free_Kalibri [48]
2 years ago
7

David has kept track of his family’s grocery bills for the past 10 weeks, as shown in the table.

Mathematics
1 answer:
Anastaziya [24]2 years ago
3 0

The data should be displayed using a line graph, as shown in the attached figure.

Definition of a Line Graph

In a line graph, also known as a line plot or a line chart, each data point is connected by its own line. A line graph displays numerical values across a chosen time span.

Why is a line graph the best choice in this situation?

A line graph would be the best option for showing the data for David's family's grocery spending over the previous 10 weeks because it would show us the trend in the data. This graph tells us of how we can recognize instances where there were significant expenses by analyzing the trend from the line graph.

Learn more about a line graph here:

brainly.com/question/16321364

#SPJ1

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WILL GIVE BRAINLIEST
SVETLANKA909090 [29]

Answer:

The correct option is A.

Step-by-step explanation:

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Let y be the profit (in millions) after x years.

From the given graph it is clear that the line passes through the point (1,-100).

The company paid for these costs and made combined profits of $80 million after 4 years. It means the graph passes through the point (4,80).

The line passes through (1,-100) and (4,80). So, the equation of line is

y-(-100)=\frac{80-(-100)}{4-1}(x-1)

y+100=\frac{180}{3}(x-1)

y+100=60(x-1)

y+100=60x-60

Subtract 100 from both sides.

y+100-100=60x-60-100

y=60x-160

The function form is

f(x)=60x-160

Therefore, the correct option is A.

6 0
3 years ago
I NEED HELP FAST what is y+1=5/6(x-2) in standard form?
Irina18 [472]

Answer:

\large\boxed{5x-6y=16}

Step-by-step explanation:

The standard form of an equation of a line:

Ax+By=C

We have the equation in the point-slope form. Convert:

y+1=\dfrac{5}{6}(x-2)\qquad\text{multiply both sides by 6}\\\\6y+6=6\!\!\!\!\diagup^1\cdot\dfrac{5}{6\!\!\!\!\diagup_1}(x-2)\\\\6y+6=5(x-2)\qquad\text{use the distributive property}\\\\6y+6=(5)(x)+(5)(-2)\\\\6y+6=5x-10\qquad\text{subtract 6 from both sides}\\\\6y+6-6=5x-10-6\\\\6y=5x-16\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-5x+6y=5x-5x-16\\\\-5x+6y=-16\qquad\text{change the signs}\\\\\boxed{5x-6y=16}

6 0
3 years ago
I need help with this...
lisov135 [29]

   ln 5
e              =    ?
                                    x
Keep in mind that y=e     and y = ln x are inverse functions of one another.
  ln 5
e       ,  we can drop both the "e" and the "ln 5."  We are left with 5 (answer).
                                                                                        ln 5
Alternatively, we could take the ln of both sides of y = e

which will result in ln y = (ln 5) ln e.  Note that ln e = 1 (these two functions are inverses of one another).

Then we are left with ln y = ln 5.  Dropping the "ln" operator from both sides,

y=5 (same as before).
8 0
3 years ago
2 (h-8)-h = h-16 what is the solution
Svetach [21]
Let's solve your equation step-by-step.<span><span><span>2<span>(<span>h−8</span>)</span></span>−h</span>=<span>h−16</span></span>Step 1: Simplify both sides of the equation.<span><span><span>2<span>(<span>h−8</span>)</span></span>−h</span>=<span>h−16</span></span><span>Simplify: (Show steps)</span><span><span>h−16</span>=<span>h−16</span></span>Step 2: Subtract h from both sides.<span><span><span>h−16</span>−h</span>=<span><span>h−16</span>−h</span></span><span><span>−16</span>=<span>−<span>16
</span></span></span>Step 3: Add 16 to both sides.<span><span><span>−16</span>+16</span>=<span><span>−16</span>+16</span></span><span>0=0</span>Answer:<span>All real numbers are solutions.</span>
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3 years ago
What’s the difference need help
labwork [276]
You would circle the 5
4 0
3 years ago
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