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Elodia [21]
2 years ago
12

x+\frac{2}{3x}-\frac{1}{27x^3}" alt="8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Reil [10]2 years ago
5 0

The solution to the expression 8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3} is \frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}

<h3>How to solve the expression?</h3>

The expression is given as:

8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3}

Take the LCM of the expression

\frac{8x^3 * 27x^3 - 4x * 27x^3 + 2 * 9x^2 - 1}{27x^3}

Evaluate the products

\frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}

Hence, the solution to the expression 8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3} is \frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

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HELP
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Answer:

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