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Elodia [21]
2 years ago
12

x+\frac{2}{3x}-\frac{1}{27x^3}" alt="8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Reil [10]2 years ago
5 0

The solution to the expression 8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3} is \frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}

<h3>How to solve the expression?</h3>

The expression is given as:

8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3}

Take the LCM of the expression

\frac{8x^3 * 27x^3 - 4x * 27x^3 + 2 * 9x^2 - 1}{27x^3}

Evaluate the products

\frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}

Hence, the solution to the expression 8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3} is \frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

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Solving for variable 'Y'.

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Simplifying
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(hope this kind of helps) :D
6 0
3 years ago
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Volgvan
Answer: Choice B) The expression (10-2x)(30-2x)x represents the volume of the box

----------------------------------------------------
----------------------------------------------------

The original width is 10 inches. The width reduces to 10-2x inches after we cut off the top two corners of the rectangle. We can think of it as taking 10 and subtracting off two copies of x like so: 10-x-x = 10-2x

Similarly, the length goes from 30 inches to 30-2x inches. This time we're taking off the top and bottom corners (focus on either side it doesn't matter). 

The height of the box is x inches due to this portion being folded up. 

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Note: the units for the answer are in cubic inches which can be written as "in^3" (inches cubed). 

6 0
3 years ago
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Answer:

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Answer:

C.

Step-by-step explanation:

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Step-by-step explanation:

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