Question

Please answer the question!

Answer 1

ANSWER

$Area = 2\sqrt{3} \: {cm}^{2}$

EXPLANATION

We need to use the Pythagoras Theorem to find the height of the triangle.

${a}^{2} + {b}^{2} = {c}^{2}$

$({2 \sqrt{3}) }^{2} + {b}^{2} = {4}^{2}$

$12 + {b}^{2} = 16$

${b}^{2} = 16 - 12$

${b}^{2} = 4$

Take positive square root to get;

$b = \sqrt{4} = 2$

Area =½bh

$Area = \frac{1}{2} \times 2\sqrt{3} \times 2$

$Area = 2\sqrt{3} \: {cm}^{2}$