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Arte-miy333 [17]
2 years ago
6

The Black Pearl is following a course that is represented by the equation. + ? = 14. . The interception course of the Flying Dut

chman is represented by the equation
Use the graphing method to determine the coordinate point where the two ships’ paths meet.
Mathematics
1 answer:
GaryK [48]2 years ago
8 0

According to the graph, the ships’ paths do not meet at any point.

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change, slope or gradient

<h3>How to determine the point where the two ships' path meet?</h3>

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2x = 5y - 40

-4x + 10y = 20

Make y the subject in the second equation, by adding 4x to both sides of the equation

4x -4x + 10y = 20 + 4x

This gives

10y = 20 + 4x

Divide both sides by 10

y = 2 + 0.4x

Substitute y = 2 + 0.4x in 2x = 5y - 40

2x = 5(2 + 0.4x) - 40

Expand

2x = 10 + 2x - 40

Subtract 2x from both sides of the equation.

2x - 2x = 10 + 2x - 2x - 40

Evaluate the like terms

0 = 10 - 40

Evaluate the like terms

0 = -30

The above equation is not true.

This means that the ships’ paths do not meet at any point.

This can be confirmed using the attached graph.

From the graph, we can see that the lines of 2x = 5y - 40 and -4x + 10y = 20 do not intersect

Hence, we can conclude that the ships’ paths do not meet at any point.

Read more about system of linear equations at

brainly.com/question/14323743

#SPJ1

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Which techniques can be used to evaluate the expression 12.75 = 1.5? Select all that apply.
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lisov135 [29]

Answer:

\left[\begin{array}{cc}2&8\\5&1\end{array}\right]

Step-by-step explanation:

The <em>transpose of a matrix </em>M^T is one where you swap the column and row index for every entry of some original matrix M. Let's go through our first matrix row by row and swap the indices to construct this new matrix. Note that entries with the same index for row and column will stay fixed. Here I'll use the notation p_{i,j} and p^T_{i,j} to refer to the entry in the i-th row and the j-th column of the matrices P and P^T respectively:

p_{1,1}=p^T_{1,1}=2\\p_{1,2}=p^T_{2,1}=5\\p_{2,1}=p^T_{1,2}=8\\p_{2,2}=p^T_{2,2}=1\\

Constructing the matrix P^T from those entries gives us

P^T=\left[\begin{array}{cc}2&8\\5&1\end{array}\right]

which is option a. from the list.

Another interesting quality of the transpose is that we can geometrically represent it as a reflection over the line traced out by all of the entries where the row and column index are equal. In this example, reflecting over the line traced from 2 to 1 gives us our transpose. For another example of this, see the attached image!

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