Answer:
f(n) = -n^2 -3n +5
Step-by-step explanation:
Suppose the formula is ...
f(n) = an^2 +bn +c
Then we have ...
f(1) = 1 = a(1^2) +b(1) +c
f(2) = -5 = a(2^2) +b(2) +c
f(3) = -13 = a(3^2) +b(3) +c
__
Here's a way to solve these equations.
Subtract the first equation from the second:
-6 = 3a +b . . . . . 4th equation
Subtract the second equation from the third:
-8 = 5a +b . . . . . 5th equation
Subtract the fourth equation from the fifth:
-2 = 2a
a = -1
Then substituting into the 4th equation to find b, we have ...
-6 = 3(-1) +b
-3 = b
and ...
1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation
5 = c
The formula is ...
f(n) = -n^2 -3n +5
Answer:
3.28
Step-by-step explanation:
find the mean of all the numbers
3 + 8 + 10 + 12 + 15 = 48
48/5=9.6
so the mean of all the numbers is 9.6
now subtract 9.6 from all the numbers
|3 - 9.6| = 6.6
|8 - 9.6| = 1.6
|10 - 9.6| = .4
|12 - 9.6| = 2.4
|15 - 9.6| = 5.4
Find the mean/average of the new values
6.6 + 1.6 + .4 + 2.4 + 5.4 = 16.4
16.4/5 = 3.28
Answer: 7.012 x 10−8 ==> Option 3
Step-by-step explanation:
(3.012 x 10−8) + (4 x 10−8)=
(3.012+4) x 10−8=
(3.012+4.000) x 10−8=7.012 x 10−8 ==> Option 3
