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cricket20 [7]
2 years ago
10

An incident response plan should be created be for a software system is released for use.

Computers and Technology
1 answer:
Nat2105 [25]2 years ago
8 0
The answer is choice “a. True”.
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What does raster graphic mean
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Raster graphics are digital images created or captured (for example, by scanning in a photo) as a set of samples of a given space. A raster is a grid of x and y coordinates on a display space. (And for three-dimensional images, a z coordinate.)
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3 years ago
What is the<br>Way to<br>keep the tool<br>Screw​
Verizon [17]
What does that even mean? is this a poem?
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2 years ago
Information flows:
Anna11 [10]

Answer:

e.

Explanation:

Information flow refers to the back and forth movement of information between different people and systems in order to communicate and perform different decision making processes. Information flows between and among supply and other internal functions and external sources. Information flow is used in just about everywhere in the world.

6 0
3 years ago
A palindrome is any word, phrase, or sentence that reads the same forward and backward. Here are some well-known palindromes: Ab
Pavlova-9 [17]

Answer:

Following are the program in the C++ Programming Language.

//header file

#include <iostream>

//header file for string

#include <string>

#include<cstring>

//using namespace

using namespace std;

//define Function to checks the string is passed is a Palindrome or not

bool is_Palin(string strng, int start_Position, int end_Position)

{

//set the if Conditional statement

if(start_Position >= end_Position)

{

return true;

}

//Check if the character is not the alphabet

if(!isalpha(strng[start_Position]))

{

//Update the starting position  

start_Position += 1;

//call Recursive function

return is_Palin(strng, start_Position++, end_Position);

}

//Check if the character is not the alphabet

if(!isalpha(strng[end_Position]))

{

//Update the end position

end_Position -= 1;

//call Recursive function

return is_Palin(strng, start_Position, end_Position--);

}

//Check if the characters are same or not same

if(tolower(strng[start_Position]) != tolower(strng[end_Position]))

{

return false;

}

//Update the positions

start_Position = start_Position + 1;

end_Position = end_Position - 1;

//call Recursive function

return is_Palin(strng, start_Position, end_Position);

}

//define Main function

int main()

{

string strng;

//get string from the user

cout << "\n\n Enter a string: ";

getline(cin, strng);

//Check for the palindrome

if(is_Palin(strng, 0, strlen(strng.c_str())-1))

{

 //then print message

cout << "\n Is a Palindrome!!!! \n";

}

//otherwise

else

{

//then print message

cout << "\n Is not a Palindrome!!!! \n";

}

return 0;

}

<u>Output:</u>

Enter a string:  Able was I, ere I saw Elba

Is a Palindrome!!!!

Explanation:

Here, we define a boolean data type function "is_Palin" to check the string which passed through is palindrome or not and pass and pass two integer type arguments for starting position and ending position and pass one string data type argument to pass string, inside the function.

  • Set the if conditional statement to check the condition if the start_position of the string is greater than end _position of the string then return true.
  • Set the if conditional statement to check the condition the start_position of the staring is alphabet then, update the start_position and call the recursion function.
  • Again set the if conditional statement to check the condition the end_position of the staring is alphabet then, update the end_position and call the recursion function.
  • Set the if conditional statement to check the condition if the start_position of the string is not equal to the end _position of the string then, return false.
  • Then, update the start_position and end _position of the string increment by 1 then, call the recursive function and then, close the function.

Finally, we define the main function and pass string through calling and passing and argument list in its parameter.  

5 0
3 years ago
Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t
Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

<em>#include<stdio.h></em>

<em />

<em>int main(int argc, char** argv){</em>

<em>    //creating pointer to read a file</em>

<em>    FILE * fp;</em>

<em>    char * line = NULL;</em>

<em>    size_t len = 0;</em>

<em>    ssize_t read;</em>

<em>    int i=0;</em>

<em>    //opening a file</em>

<em>    fp = fopen(argv[1], "r");</em>

<em>    //handling the error condition</em>

<em>    if (fp == NULL){</em>

<em>        printf("File not found..!!");</em>

<em>        return 0;</em>

<em>    }</em>

<em>    int moreThan50 =0;</em>

<em>    //reading a file line by line</em>

<em>    while ((read = getline(&line, &len, fp)) != -1) {</em>

<em>        i = 0;</em>

<em>        if(read >= 50){</em>

<em>            moreThan50++;</em>

<em>        }</em>

<em>        while(i < read){</em>

<em>            if(line[i]!='\n'){</em>

<em>                if(i%50 == 0){</em>

<em>                    printf("\n%c",line[i]);</em>

<em>                }else{</em>

<em>                    printf("%c",line[i]);</em>

<em>                }</em>

<em>            }</em>

<em>            i++;</em>

<em>        }</em>

<em>    }</em>

<em>    printf("\nTotal lines over 50 chars: %d\n",moreThan50);</em>

<em>    printf("Offending Lines: ");</em>

<em>    for(i=1;i<=moreThan50;i++)</em>

<em>        printf("%d, ",i);</em>

<em>    fclose(fp);</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

4 0
2 years ago
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