Answer:
Two hundred seventy three thousand and fifty .
Step-by-step explanation:
Given : (27 thousands 3 hundreds 5 ones) x 10
Solution:
27 thousands 3 hundreds 5 ones = 27,305
So, 

Periods are counted from last .
The 1st period consists of ones, tens and hundred.
The 2nd period consists of thousand, 10 thousand and 100 thousands.
The 3rd period consists of million, 10 million and 100 million.
So, 273,050 is Two hundred seventy three thousand and fifty
Hence (27 thousands 3 hundreds 5 ones) x 10 is Two hundred seventy three thousand and fifty .
Answer:
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Step-by-step explanation:
Answer: No, it can never be greater. At most it can be equal though.