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stich3 [128]
1 year ago
8

Gcf of 12h3,36h3,12h6

Mathematics
1 answer:
aliya0001 [1]1 year ago
3 0

The greatest common factor from the given information is 12h³.

<h3>What is the greatest common factor?</h3>

The greatest common factor (GCF) of a given set of whole numbers is the largest value that can be divided by the set of numbers.

From the information given, we are to find the GCF of:

12h³ = (1 , 2, 3, 4, 6 , 12 )h³

36h³ = (1, 2, 3, 4, 6, 9, 12, 18, 36)h³

12h⁶ = (1, 2, 3, 4, 6, 12)h³ * h³

Therefore, we can conclude that the greatest common factor is 12h³.

Learn more about the greatest common factor here:

brainly.com/question/219464

#SPJ1

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Step-by-step explanation:

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3 years ago
Is 976 -522 more or less than 400? Explain how you can tell without actually subtracting.
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The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0
4 years ago
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