The answer would be iii: 10-15%
the way to find this is to divide 43 by 381 to get 11.2% which falls in the rage of 10-15%
Amount of liquid plant fertilizer in the container that the gardener has = 6 1/5 pounds
= 31/5 pounds
We already know that 1 pound = 16 ounce
Then
Amount of liquid plant fertilizer in the
container that the gardener has = (31/5) * 16 ounce
= 496/5 pounds
Amount of liquid plant fertilizer that the gardener uses on Sunday = 2 1/2 ounces
= 5/2 ounces
Then
The amount of liquid plant fertilizer that are left= (496/5) - (5/2) ounces
= (992 - 25)/10 ounces
= 967/10 ounces
= 96.7 ounces
So the total amount of liquid plant fertilizer left is 96.7 ounces.
Answer:
The test statistics is
The p-value is 
Step-by-step explanation:
From the question we are told
The West side sample size is 
The number of residents on the West side with income below poverty level is 
The East side sample size 
The number of residents on the East side with income below poverty level is 
The null hypothesis is 
The alternative hypothesis is 
Generally the sample proportion of West side is

=> 
=> 
Generally the sample proportion of West side is

=> 
=> 
Generally the pooled sample proportion is mathematically represented as

=> 
=> 
Generally the test statistics is mathematically represented as
![z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2} ]} }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B%5C%5E%20%7Bp%7D_1%20-%20%5C%5E%7Bp%7D_2%7D%7B%5Csqrt%7Bp%281-%20p%29%20%5B%5Cfrac%7B1%7D%7Bn_1%20%7D%20%2B%20%5Cfrac%7B1%7D%7Bn_2%7D%20%20%5D%7D%20%20%7D)
=>
=>
Generally the p-value is mathematically represented as

From z-table
So

Can you be more specific on the problem