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aleksandrvk [35]
2 years ago
10

Where is the horizontal center of mass of the entire upper extremity?

Mathematics
1 answer:
mixas84 [53]2 years ago
7 0

Answer:

can you tell me please

Step-by-step explanation:

nicest

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Use exterior angles to show that the angle sum of quadrilateral PQRS is 360°.​
Shkiper50 [21]

Answer:

I don't really know but one triangle is 180 degrees so two added together is 360 degrees...

but ohh I remembered

a=c+d (since a+b=180 and c+d+b=180)

e=g+h (since e+f=180 and g+h+f= 180)

and the fact is that c+d+g+h+b+f=the angle sum of quadrilateral PQRS

a+e+b+f= the angle sum of quadrilateral PQRS (by substitutions)

a+e+b+f=360 (four angles are from one origin so it's 360 degrees )

8 0
3 years ago
Which of the following could explain the changes in growth between the 15th month and the 24th month ?
noname [10]

Answer:  The Answer is A

Step-by-step explanation:

i think it's right

6 0
3 years ago
The sum of all prime factors of<br>of<br>x is<br>20. Find the value​
OLga [1]

Answer:

no clue

Step-by-step explanation:

but good luck i belive in yoyu

3 0
3 years ago
Please help ill give brainliest, and explain the answer too please
Basile [38]

Answer:

x^2+2

Step-by-step explanation:

since (x^2+2x+1) is negative from the subtraction symbol in front, the entire thing turns negative. The equation turns into 2x^2+2x+3-x^2-2x-1=...

if you solve this equation you will get x^2+2 by adding the like terms together

3 0
3 years ago
What is limit of f(x) = (x^3-2x^2-9x+4)/(x^2-2x-8) as x approaches 4
sattari [20]
\displaystyle\lim_{x\to4}\frac{x^3-2x^2-9x+4}{x^2-2x-8}

First notice that x^2-2x-8=(x-4)(x+2). If x-4 is not a factor of the numerator, then there is a non-removable discontinuity at x=4, and a removable discontinuity otherwise.

You have 4^3-2\times4^2-9\times4+4=0, which means, by the polynomial remainder theorem, that x-4 is indeed a linear factor of the numerator. Dividing yields a quotient of

\dfrac{x^3-2x^2-9x+4}{x-4}=x^2+2x-1

so the limit is

\displaystyle\lim_{x\to4}\frac{x^2+2x-1}{x+2}=\frac{4^2+2\times4-1}{4+2}=\frac{23}6
6 0
3 years ago
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