Answer:
123456789098765432
Explanation:
asdfghjklokjhgfdsasertyujn nbgfdfvbnjujhgvfcdec vgfredfghjmk
Answer:
Following are the code to this question:
#include <iostream> //defining header file
using namespace std;
void numbers(ostream &outs, const string& prefix, unsigned int levels); // method declaration
void numbers(ostream &outs, const string& prefix, unsigned int levels) //defining method number
{
string s; //defining string variable
if(levels == 0) //defining condition statement that check levels value is equal to 0
{
outs << prefix << endl; //use value
}
else //define else part
{
for(char c = '1'; c <= '9'; c++) //define loop that calls numbers method
{
s = prefix + c + '.'; // holding value in s variable
numbers(outs, s, levels-1); //call method numbers
}
}
}
int main() //defining main method
{
numbers(cout, "THERBLIG", 2); //call method numbers method that accepts value
return 0;
}
Output:
please find the attachment.
Explanation:
Program description:
- In the given program, a method number is declared, that accepts three arguments in its parameter that are "outs, prefix, levels", and all the variable uses the address operator to hold its value.
- Inside the method a conditional statement is used in which string variable s and a conditional statement is used, in if the block it checks level variable value is equal to 0. if it is false it will go to else block that uses the loop to call method.
- In the main method we call the number method and pass the value in its parameter.
Answer:
These are the supplies in the list:
[‘pencil’, ‘notebook’, ‘backpack’, ‘pen’, ‘calculator’]
Explanation:
The line return (\n) character will be in the output (so there will be a change of line), but it will NOT be visible as it would have been interpreted as a special character.
So the output will be on 2 different lines, with no \n visible.
If the command would have been: print('These are the supplies in the list:\n', supplies), with single quotes (') instead of double quotes (") then then \n would have been printed but not interpreted as a special character. At least in most computer language. Since we don't know of which language the question refers to, we can't be sure at 100%.
Answer:
In a <u>little endian computer</u> -The data's least substantial byte is put at the lower address byte. The remaining information will be put in memory in order in the next three bytes.
a)1234
4 is placed at the least significant bits,so this byte stored at lower memory address.
1 is placed at the most significant bits,so this byte stored at higher memory address.
b) ABFC
C is placed at the least significant bits,so this byte stored at lower memory address.
A is placed at the most significant bits,so this byte stored at higher memory address.
c) B100
0 is placed at the least significant bits,so this byte stored at lower memory address.
B is placed at the most significant bits,so this byte stored at higher memory address.
d) B800
0 is placed at the least significant bits,so this byte stored at lower memory address.
B is placed at the most significant bits,so this byte stored at higher memory address.
