The mass of the acetic acid is 1.512 g.
<h3 /><h3>What is Molarity?</h3>
molarity is the concentration of a substance in mol per dm³
From the question,
The number of moles contained in the 30 mL vinegar is
- n = (0.84×30)/1000
- n = 0.0252 mol.
the molar mass of vinegar is calculated below.
- m.m of (HC₂H₃O₂) = [1+(12×2)+(1×3)+(16×2)]
- m.m = (1+24+3+32]
- m.m = 60 g/mol.
To calculate the mass of acetic acid, we use the formula below.
- R.m = n×m.m............. Equation 1
Where
- R.m = mass of acetic acid.
Substitute these values into equation 1
- R.m = (0.0252×60)
- R.m = 1.512 g.
Hence, The mass of the acetic acid is 1.512 g.
Learn more about molarity here: brainly.com/question/20383725
In terms of communication, information is expressed either as the content of a message or through direct or indirect observation. That which is perceived can be construed as a message in its own right, and in that sense, information is always conveyed as the content of a message.
Information can be encoded into various forms for transmission and interpretation (for example, information may be encoded into a sequence of signs, or transmitted via a signal). It can also be encrypted for safe storage and communication.
Based on the vertices and the pre-order traversal order the tree would be visited is e, i, b, h, f, a, c, d, g.
<h3>What order will the tree be visited?</h3>
When using the pre-order traversal, the order would be from the root child node to the left child node to right child node.
The root node is the highest node which is e. From here you'll then proceed to the left roots first which means you'll go to i and then b.
From there you go to h and then f. The next nodes would be a and c.
Continuing from left to right, you'll then go to d and then g.
You'll therefore start from "e" and move to "i" and then "b" to "h" and then "f" and "a" to "c" and then to "" and finally to "g"
Find out more on the pre-order traversal at brainly.com/question/14559964.
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Based on the information given, it has been computed that the activation energy will be 105.8Kj.
<h3>How to calculate activition energy</h3>
From the information given,
T1 = 25 + 273 = 298K
T2 = 35 + 273 = 308J
R = 8.314J/mol
K2/K1 = 4
Therefore,
log(4) = E/(2.303 × 8.314) × [10/(298 × 308)]
= (0.602 × 2.303 × 8.314 × 298 × 308) / 10
= 105.8KJ
Therefore, the activation energy is 105.8KJ.
Learn more about activation energy on:
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