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2 years ago

5

Express sin S as a fraction in simplest terms. R S

1 answer:

enyata [817]2 years ago

5 0

Answer:

$\sf Sin \ S = \dfrac{2}{9}$

Step-by-step explanation:

<h3>Trigonometry ratios:</h3>

$\sf \boxed{\bf Sin \ S = \dfrac{opposite \ side \ of \ \angle S}{hypotenuse}}$

$\sf = \dfrac{RQ}{SQ}\\\\= \dfrac{2}{9}$

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Rudiy27

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3 years ago

Due by the end of the day please help, 15<br> points

liberstina [14]

We have an inscribed angle here. Angle YXZ is an inscribed angle.

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Angle YXZ = (1/2)(arc YZ)

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Done!

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3 years ago

For the differential equation dy/dt=ky, k is a constant, y(0)=24, and y(1)=18. What is the value of k?

Gre4nikov [31]

The equation is separable, so solving it is trivial:

$\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt$

Integrating both sides gives

$\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}$

Given $y(0)=24$ and $y(1)=18$ , we find

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so the answer is E.

8 0

4 years ago

Read 2 more answers

A bacteria population doubles every minute. Explain why this population growth cant be modeled on a graph

Kisachek [45]

Answer:

It can be modeled on an exponential graph

Step-by-step explanation:

Bacteria is <u><em>doubling</em></u> by the minute. This means that if there are 2 bacteria in the first minute, there would be 4 in the second, 8 in the third, 16 in fourth, and so on. This can be modeled using an exponential graph, where a number is constantly increasing by multiplying.

3 0

3 years ago

Find (f ∘ g)(-6) when f(x) = 9x + 2 and g(x) = -9x2 - 2x + 1.

Salsk061 [2.6K]

Given that the two functions are $f(x)=9x+2$ and $g(x)=-9x^2-2x+1$

We need to determine the value of $(f \circ g)(-6)$

<u>The value of </u> $(f \circ g)(x)$ <u>:</u>

The value of $(f \circ g)(x)$ can be determined using the formula,

$(f \circ g)(x)=f[g(x)]$

Substituting $g(x)=-9x^2-2x+1$ in the above formula, we get;

$(f \circ g)(x)=f[-9x^2-2x+1]$

Now, substituting $x=-9 x^{2}-2 x+1$ in the function $f(x)=9x+2$ , we get;

$(f \circ g)(x)=9(-9x^2-2x+1)+2$

$(f \circ g)(x)=-81x^2-18x+9+2$

$(f \circ g)(x)=-81x^2-18x+11$

Thus, the value of $(f \circ g)(x)$ is $(f \circ g)(x)=-81x^2-18x+11$

<u>The value of </u> $(f \circ g)(-6)$ <u>:</u>

The value of $(f \circ g)(-6)$ can be determined by substituting x = -6 in the function $(f \circ g)(x)=-81x^2-18x+11$

Thus, we have;

$(f \circ g)(-6)=-81(-6)^2-18(-6)+11$

$(f \circ g)(-6)=-81(36)-18(-6)+11$

$(f \circ g)(-6)=-2916+108+11$

$(f \circ g)(-6)=-2797$

Thus, the value of $(f \circ g)(-6)$ is -2797

Hence, Option B is the correct answer.

8 0

4 years ago