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2 years ago

4. A 40 foot ladder is leaning against the side of a building. If the bottom of the ladder is 24

1 answer:

8 0

First you start by drawing a right triangle. the longest side is the length of the ladder (40ft) and will be represented by variable c. Label the vertical side as a and the horizontal side as b(24 ft).

we will use a^2 +b^2 =c^2 to find it. plug in the variables and it will be a^2 + 24^2 = 40^2 which simplifies to a^2 + 576 = 1600. you then isolate the variable by subtracting 576 from 1600. our new equation is a^2 = 1024. we take the sqrt of a^2 and 1024 so our final equation is a=32 ft. the answer is 32 feet.

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4 years ago

The 9th graders are selling tickets to raise money for a class field trip. They are selling student tickets for $5 and adult tic

Marina CMI [18]

Answer:

Total number of adult tickets sold = 10

Total Number of Students tickets sold = 30

Step-by-step explanation:

Let $x$ be the number of student tickets sold.

Let $y$ be the number of adult tickets sold.

As per the question statement, total tickets sold are 40.

$x +y =40 ...... (1)$

Price of each student ticket = $5

Sales from students' tickets = Price of each students ticket $\times$ Number of students tickets sold

Sales from student's tickets = 5 $\times x$

Price of each adult ticket = $9

Sales from adult's tickets = Price of each adult's ticket $\times$ Number of adult tickets sold

Sales from student's tickets = 9 $\times y$

Total sales is done by students and adult tickets is $240 as per the question statement.

$\Rightarrow 5x + 9y = 240 ......(2)$

Solving equations (1) and (2) using elimination method:

Equation $(2) - 5 \times (1)$ :

$5x + 9y -5x-5y = 240-200\\\Rightarrow 4y = 40\\\Rightarrow y =10$

Total number of adult tickets sold = 10

Putting $y=10$ in equation (1):

$x+10 = 40\\\Rightarrow x = 30$

Total number of students tickets sold = 30

Total number of adult tickets sold = 10

Total Number of Students tickets sold = 30

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3 years ago

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$\left[\begin{array}{ccc}-1&3\\5&4\end{array}\right] \cdot \left[\begin{array}{ccc}0&-2&6\\1&-3&2\end{array}\right]\\\\= \left[\begin{array}{ccc}(-1)(0)+(3)(1)&(-1)(-2)+(3)(-3)&(-1)(6)+(3)(2)\\(5)(0)+(4)(1)&(5)(-2)+(4)(-3)&(5)(6)+(4)(2)\end{array}\right]\\\\= \left[\begin{array}{ccc}0+3&2-9&-6+6\\0+4&-10-12&30+8\end{array}\right]\\\\ =\left[\begin{array}{ccc}3&-7&0\\4&-22&38\end{array}\right]$