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3 years ago

Which of the following is the equation of a trend line for the scatter plot below?

Mathematics

1 answer:

dybincka [34]3 years ago

7 0

I am pretty sure that it is C. because i did the math on my sheet and that the closest answer to what i got

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Write the equation of a line that is perpendicular to x=3x=3x, equals, 3 and that passes through the point (0,-4)(0,−4)left pare

leva [86]

Answer: $x+3y=12$

Step-by-step explanation:

Slope of two lines that are perpendicular to each other is 1.

If one line is $y=3x$ , then its slope = 3 [by comparing to the linear equation y= mx+c, here m=3]

Let n be the slope of the required line, then

$n\times3=-1\\\\\rightarrow\ n=\dfrac{-1}{3}$

Equation of line with slope n and passers through (a,b) is

$(y-b)=n(x-a)$

Equation of line with slope n= $\dfrac{-1}{3}$ and passes through point ( 0,-4) :

$(y-(-4))=\dfrac{-1}{3}(x-0)\\\\\Rightarrow\ y+4=\dfrac{-1}{3}x\\\\\Rightarrow\ -3(y+4)=x\\\\\Rightarrow-3y-12=x\\\\\Rightarrow x+3y=12$

Hence, Required equation : $x+3y=12$

8 0

2 years ago

The wind speed s (in miles per hour) is related to the distance (in miles) the tornado travels by the equation s = 93log d + 65.

Vesnalui [34]

Answer:

The distance the tornado traveled was approximately 205 miles.

Step-by-step explanation:

The equation representing the relationship between the wind speed (in miles per hour) and the distance the tornado travels (in miles) is:

$s=93\log d+65$

Compute the value of <em>d</em> for <em>s</em> = 280 as follows:

$s=93\log d+65$

$280=93\log d+65$

$93\log d=280-65\\93\log d=215$

$\log d=2.312\\$

$d=10^{2.312}\\d=205.035\\d\approx 205$

Thus, the distance the tornado traveled was approximately 205 miles.

7 0

2 years ago

Please please help me -

Hitman42 [59]

Answer:

Step-by-step explanation:

7 0

2 years ago

Which value of gg makes 26=7(g-9)+ 12 a true statement?

Nezavi [6.7K]

G=11 you add all the numbers together to get the correct number

3 0

2 years ago

Solve for the missing sides 30-60-90 triangle show work please and thank you

Alex_Xolod [135]

Answer:

$x=8\sqrt{3}$

$y=16$

$x=3$

$y=3\sqrt{3}$

Step-by-step explanation:

The sides of a (30 - 60 - 90) triangle follow the following proportion,

$a-a\sqrt{3}-2a$

Where (a) is the side opposite the (30) degree angle, ( $a\sqrt{3}$ ) is the side opposite the (60) degree angle, and (2a) is the side opposite the (90) degree angle. Apply this property for the sides to solve the two given problems,

It is given that the side opposite the (30) degree angle has a measure of (8) units. One is asked to find the measure of the other two sides.

The measure of the side opposite the (60) degree side is equal to the measure of the side opposite the (30) degree angle times ( $\sqrt{3}$ ). Thus the following statement can be made,

$x=8\sqrt{3}$

The measure of the side opposite the (90) degree angle is equal to twice the measure of the side opposite the (30) degree angle. Therefore, one can say the following,

$y=16$

In this situation, the side opposite the (90) degree angle has a measure of (6) units. The problem asks one to find the measure of the other two sides,

The measure of the side opposite the (60) degree angle in a (30-60-90) triangle is half the hypotenuse times the square root of (3). Therefore one can state the following,

$y=3\sqrt{3}$

The measure of the side opposite the (30) degree angle is half the hypotenuse (the side opposite the (90) degree angle). Hence, the following conclusion can be made,

$x=3$

6 0

2 years ago