Answer:
Step-by-step explanation:
To make the problem easier to solve, we will set it up as the equation of the length of time of each class times the number of classes equals the total amount of minutes. However, since we don't know the number of classes, we'll symbolize our two unknowns with two variables.
75x + 45y = 705
(75x + 45y)/15 = 705/15
5x + 3y = 47
y = (47-5x)/3
It looks like we can't simplify the equation any more, so now it is a matter of trial and error. The minimum number of Saturday classes means the maximum number of weekday classes. We first will test for the maximum by assuming there are no Saturday classes, then will work our way up until x is an integer.
If x = 0
(47-5(0))/3 = 47/3 = 15.6666
If x = 1
(47-5(1))/3 = 42/3 = 14
This works. Therefore, the maximum number of weekday classes is 14, or choice b.
The slope of the line would be 3/2 because the slope formula would be y2-y1/x2-x1 so 3-0=3 and 4-2=2 so 3/2
Hope this helps
Have a great day/night
Feel free to ask any questions
Answer:
The value of Discriminant of the function is -92
It has ZERO distinct real number zeros.
Step-by-step explanation:
Given:

Which is a Quadratic Equation in the general form of

where a,b and c are constants.So on comparing the given equation with general form we get,

Formula for discriminant we have

now for zeros we have

on substituting these values we get

or

the term
is imaginary
hence the zeros are not real number