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3 years ago

Seven is at most the quotient of a number d and −5(what is the inequality?)

2 answers:

8 0

Answer: 7≤ d/-5

At most=7 cannot be more than, but can be equal to.
Quotient: The resulting answer after one number is divided by another.

Angelina_Jolie [31]3 years ago

5 0

Answer:

$7 \leq -\displaystyle\frac{d}{5}$

$-7 \geq \displaystyle\frac{d}{5}$

Step-by-step explanation:

We have to form an inequality with the given information.

The quotient of a number d and -5 is given by:

$\displaystyle\frac{d}{-5} = -\displaystyle\frac{d}{5}$

Now, this inequality is at most 7 that is the above expression can have the value of seven or less.

This can be written as:

$7 \leq -\displaystyle\frac{d}{5}$

Multiplying both sides by -1, we have:

$-7 \geq \displaystyle\frac{d}{5}$

Thus, $7 \leq -\displaystyle\frac{d}{5}$ is the required inequality.

You might be interested in

Evaluate the function g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.

Roman55 [17]

Evaluate the function

g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.

This is tedious math work but necessary to sharpen your skills.

Let x = -2

g(-2) = 2(-2)^2 + 3(-2) – 5

g(-2) = 2(4) - 6 - 5

g(-2) = 8 - 11

g(-2) = -3

Now let x = 0 and repeat the process.

g(0) = 2(0)^2 + 3(0) - 5

g(0) = 0 + 0 - 5

g(0) = -5

Lastly, let x = 3.

g(3) = 2(3)^2 + 3(3) - 5

g(3) = 2(9) + 9 - 5

g(3) = 18 + 9 - 5

g(3) = 27 - 5

g(3) = 22

Did you follow through each step?

4 0

3 years ago

Can someone do this for me ahhhh

Aleksandr [31]

28:13 is the answer i’m pretty for sure

4 0

3 years ago

Part I - To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nico

IRINA_888 [86]

Answer:

(I) 99% confidence interval for the mean nicotine content of this brand of cigarette is [24.169 mg , 30.431 mg].

(II) No, since the value 28.4 does not fall in the 98% confidence interval.

Step-by-step explanation:

We are given that a new cigarette has recently been marketed.

The FDA tests on this cigarette gave a mean nicotine content of 27.3 milligrams and standard deviation of 2.8 milligrams for a sample of 9 cigarettes.

Firstly, the Pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean nicotine content = 27.3 milligrams

s = sample standard deviation = 2.8 milligrams

n = sample of cigarettes = 9

$\mu$ = true mean nicotine content

Here for constructing 99% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

Part I : So, 99% confidence interval for the population mean, $\mu$ is ;

P(-3.355 < $t_8$ < 3.355) = 0.99 {As the critical value of t at 8 degree

of freedom are -3.355 & 3.355 with P = 0.5%}

P(-3.355 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 3.355) = 0.99

P( $-3.355 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $3.355 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-3.355 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+3.355 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-3.355 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+3.355 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $27.3-3.355 \times {\frac{2.8}{\sqrt{9} } }$ , $27.3+3.355 \times {\frac{2.8}{\sqrt{9} } }$ ]

= [27.3 $\pm$ 3.131]

= [24.169 mg , 30.431 mg]

Therefore, 99% confidence interval for the mean nicotine content of this brand of cigarette is [24.169 mg , 30.431 mg].

Part II : We are given that the FDA tests on this cigarette gave a mean nicotine content of 24.9 milligrams and standard deviation of 2.6 milligrams for a sample of n = 9 cigarettes.

The FDA claims that the mean nicotine content exceeds 28.4 milligrams for this brand of cigarette, and their stated reliability is 98%.

The Pivotal quantity for 98% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean nicotine content = 24.9 milligrams

s = sample standard deviation = 2.6 milligrams

n = sample of cigarettes = 9

$\mu$ = true mean nicotine content

Here for constructing 98% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 98% confidence interval for the population mean, $\mu$ is ;

P(-2.896 < $t_8$ < 2.896) = 0.98 {As the critical value of t at 8 degree

of freedom are -2.896 & 2.896 with P = 1%}

P(-2.896 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.896) = 0.98

P( $-2.896 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.896 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.896 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.896 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.896 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.896 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $24.9-2.896 \times {\frac{2.6}{\sqrt{9} } }$ , $24.9+2.896 \times {\frac{2.6}{\sqrt{9} } }$ ]

= [22.4 mg , 27.4 mg]

Therefore, 98% confidence interval for the mean nicotine content of this brand of cigarette is [22.4 mg , 27.4 mg].

No, we don't agree on the claim of FDA that the mean nicotine content exceeds 28.4 milligrams for this brand of cigarette because as we can see in the above confidence interval that the value 28.4 does not fall in the 98% confidence interval.

5 0

3 years ago

I need help and I SUCK at mathematics can yall help me I'm in 5th grade

nalin [4]

Answer:

Step-by-step explanation:

1 1/4 = 1.25

1 4/5 = 1.8

1.8+1.25=3.05=3 1/20

6 0

3 years ago

Read 2 more answers

Eloise made a list of some multiples of 8/5 write 5 fractions that can be in Eloise list

alexgriva [62]

This question is asking for a list of fractions, that when you pull out common factors, they will all simplify back to the 8/5 fraction.

So if 2 is the common factor, you multiply the numerator and denominator by 2.

2: (8*2)/(5*2)= 16/10

3: (8*3)/5*3)= 24/15

4: (8*4)/(5*4)= 32/20

5: (8*5)/(5*5)= 40/25

10: (8*10)/5*10)= 80/50

Eloise's Potential List:
16/10, 24/15, 32/20, 40/25, 80/50

If you simplify any of these fractions above, you will get 8/5 again.

To work backwards:
80/50: 10 goes into 80, 10 goes into 50= 8/5

16/10: 2 goes into 16, 2 goes into 10= 8/5

Hope this helps! :)

4 0

3 years ago