Full question :
A man buys a certain number of oranges at 20 for Rs. 60 and an equal number at 30 for Rs. 60. He mixes them and sells them at 25 for Rs. 60. What is the gain or loss percent?
Answer:
4% loss(percentage loss on cost price)
Step-by-step explanation:
we will be employing algebra in solving this problem :
20 oranges at 60 Rs=60Rs/20 per orange=3Rs per orange
Say x oranges bought at 3Rs per orange=3Rsx
Equal number of oranges at 30 oranges for 60 Rs=60Rs/30 per orange=2Rs per orange
Say x oranges bought at 3Rs per orange=2Rsx
Total Cost Price = 3Rsx + 2Rsx = 5Rsx
He then sells all oranges at 25 for 60 Rs
Therefore price per orange=60/25=12/5Rs
since he sold x+x oranges(from the above calculations)
Total selling price=total oranges *12/5Rs=2x oranges*12/5Rs=24x/5Rs
Profit or loss=24x/5-5x=-x/5
therefore we have a loss =-x/5
Percentage of loss(on cost price)
=x/5÷5x∗100=
=1/25∗100=4%
