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Elenna [48]
2 years ago
9

The following statements are all incorrect. Explain the statements and the errors fully using the probability rules discussed in

topic two. 1.The number 7 is a lucky number so you are more likely to win raffles with ticket number 7 than with a different number. 2.I roll two dice and add the results. The probability of getting a total of 8 is 1/12 because there are 12 different possibilities and 8 is one of them. 3.Mr. Verde has to have a major operation. Ninety-three percent of the people who have this operation make a complete recovery. There is a 93% chance that Mr. Verde will make a complete recovery if he has this operation.4.The Ramblers play the Chargers. The Ramblers can win, loose, or draw, so the probability that they win is 1/3. 5.I have flipped an unbiased coin four times and got heads. It is more likely to get tails the next time I flip it.6.Thirty random college students are asked if they study during the week. Since 60% said yes, a statement can be made that 40% of students only study on the weekend.
Mathematics
2 answers:
bija089 [108]2 years ago
3 0

The reasons for each incorrect statement are as follows;

  1. The error in the statement is that, there might be other luckier numbers compared to number 7 and hence, the statement does not hold true for all numbers.
  2. The statement is incorrect because, there are 36 different possibilities and there are 5 possibilities of getting an 8.
  3. The statement is incorrect because, 93% does not necessarily represent a 93% chance of complete recovery as this is subject to other variables.
  4. The probability that they win is not 1/3 as it is subject to what the results have been over the years and not just the possible results.
  5. Since, the coin is unbiased, it follows that upon flipping the coin for the fifth time, it is not likely to have tails the next time it is flipped.
  6. The statement is incorrect because some students study during the week and weekends, hence, the conclusion is not correct.

<h3>What is Probability?</h3>

The term probability put simply is the ratio of the desired outcome to the possible outcomes. It therefore follows that probability as the name implies is used to predict the chance of an occurrence.

Read more on probability;

brainly.com/question/24756209

#SPJ1

irinina [24]2 years ago
3 0

The probability is illustrated below.

<h3>How to illustrate the probability?</h3>

1) Raffles game is a gambling competition in which people get numbered tickets and each number has an equal chance of winning.

2) When two dice are rolled then there will be totally 36 outcomes. Of those the outcomes with sum 8 are (2,6),(3,5),(4,4),(5,3),(6,2).

These are 5 in number.

So,P( sum =8)= 5/36.

3)This is a true statement.

4) Here win, lose, or tie is just the outcomes where their probabilities are different from each other and those values depend upon different situations.

5) Tossing a coin is a random experiment which means that the result of the experiment (ie head or tail) cannot be predicted.

6) If 60% said yes to " study during the week" then 40% will say yes to "either won't study or study at weekend".

7) When two coins are tossed, the outcomes are as follows

H,H

H,T

T,H

T,T.

So, P( head, tail ) =2/4 =1/2

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

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Find the 7th term of the geometric sequence whose common ratio is 1/3 and whose first term is 5.
wolverine [178]

Answer:

t_7 =\frac{5}{729}

Step-by-step explanation:

We are given that:

First term (a) = 5

common ratio (r) =\frac{1}{3}

The nth term of a geometric sequence is given as:

t_n =ar^{n-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{7-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \frac{1}{729}\\\\\huge\red{\boxed{\therefore t_7 =\frac{5}{729} }}

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Suppose that shoe sizes of American women have a bell-shaped distribution with a mean of 8.47 and a standard deviation of 1.5. U
alex41 [277]

Answer:

2.5% of American women have shoe sizes that are greater than 11.47.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 8.47

Standard deviation = 1.5

The normal distribution is symmetric, which means that half the measures are below the mean, and half are above the mean.

What percentage of American women have shoe sizes that are greater than 11.47?

11.47 = 8.47 + 2*1.5

This means that 11.47 is two standard deviations above the mean.

Of those measures below the mean, none are greater than 11.47.

Of those measures above the mean, 95% are between the mean and 11.47, and 5% are above. So

0.5*0.05 = 0.025

2.5% of American women have shoe sizes that are greater than 11.47.

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A bag contains five white marbles and five black marbles. What is the probability of drawing a white marble, not replacing it, a
Lelu [443]

~ ANSWER=1/2 ~

Simple probability is found by counting all the results which fit requirements and dividing by all possible results.

To find probability of two results in a row, multiply chance of first result by chance of second result.

Since you are replacing the marble before the second draw, we don’t have to figure out the various changes in odds for the different possible first draws. It’s just that simple.

There are 5 white marbles

There are 4 red marbles

There are always 20 marbles in all

5/20*4/20=1/4*1/5=1/20 or 1/2

By coincidence, the same as the chance of drawing the white marble in one draw.

6 0
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