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bulgar [2K]
3 years ago
11

Tips for Success Read the assignment carefully and make sure you answer each part of the question or questions Check your work w

hen you're done. Your Assignment Miguel is building a doghouse. He cuts one sheet of wood to make the front wall. He also cuts out a door that is 2 feet by 2 feet. The dimensions, in feet, are shown in the diagram. 2 ft 317​
Mathematics
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer:

What’s the answer

Step-by-step explanation:

?

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A volleyball team won 90% of 80 games played.how many games did they win?
andreyandreev [35.5K]

Answer:

72 games won

Step-by-step explanation:

4 0
3 years ago
To solve the inequality m/-7<(or equal to) 14 , what should be done to both sides?
Marizza181 [45]

Answer:

\large\boxed{m\geq-98}

Step-by-step explanation:

\dfrac{m}{-7}\leq14\\\\-\dfrac{m}{7}\leq14\qquad\text{change the signs}\\\\\dfrac{m}{7}\geq-14\qquad\text{multiply both sides by 7}\\\\7\!\!\!\!\diagup^1\cdot\dfrac{m}{7\!\!\!\!\diagup_1}\geq(7)(-14)\\\\m\geq-98

5 0
3 years ago
Read 2 more answers
A kangaroo hops 2 kilometers in 3 minutes. At this rate, how far does the kangaroo travel in 2 minutes? *
Dmitrij [34]

Answer:

At a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would travel 1,333 km.

Step-by-step explanation:

If a kangaroo hops 2 kilometers in 3 minutes, to calculate how much distance this animal hops in 2 minutes, the following calculation should be performed:

2 km / 3 min = 0.666 km per minute (2/3 x 2)

0.666 km per minute x 2 minutes = 1.333 kilometers in 2 minutes (0.666 x 2)

Therefore, at a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would hop 1,333 km.

5 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. An article gave the ac
Mnenie [13.5K]

Answer:

Attached as image png.

Step-by-step explanation:

The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. An article gave the accompanying sample observations on breakdown voltage (kV) of a particular circuit under certain conditions. 62 51 53 58 42 54 56 61 59 64 51 53 64 62 50 68 54 55 57 50 55 50 56 55 46 56 54 55 53 47 48 56 58 48 63 58 57 56 54 59 54 52 50 55 60 51 56 59 Construct a boxplot of the data.

The boxplot is a method to represent a series of numerical data through their quartiles. In this way, the box diagram shows at a glance the median and quartiles of the data.

4 0
3 years ago
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