The upper quartile for the given data is 51 .
Given data: {51,49,52,46,50,38,38,45,34,52,46}
Data in arranged form: {34,38,38,45,46,46,49,50,51,52,52}
Find the median first, then the upper quartile. There are eleven data points, thus look at term six to determine the median as there are five data points on any side. The median is 46 because the sixth term is 46.
The upper extreme, 52, and the median are then used to determine the upper quartile; make sure not to include the median data point when dividing the groups. The upper quartile is the third term (between the median and upper extreme) because there would be two data points on each side if there were only five data points from the median to the upper extreme. The third term, which is 51, falls into the upper quartile.
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