The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
$36.8
Step-by-step explanation:
Answer:
<h2>
x
- x - 6</h2><h2 />
Step-by-step explanation:
Multiply each term in the first parentheses by each term in the second parentheses ( FOIL)
Calculate the product
Collect like terms
Hope this helps..
Best regards!
These words are represented as homophones as they sound alike but have the different meanings.
Please use " ^ " to denote exponentiation:
<span>f(x) = –(x + 8)^2 – 1
Find the first derivative: f '(x) = -2(x+8)(1)
Set this = to 0: -2(x+8) = 0
solve for x: x = -8
Divide the number line into subintervals based upon x=-8:
(-inf, -8) and (-8, inf)
Choose a test value for x from each interval, e. g., -10 from the first interval and 20 from the second.
Subst. this test value into the derivative, shown above.
If the result is + the function is incr on that interval; if - the fn. is decr.
Questions welcome!</span>
