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pochemuha
2 years ago
11

F(x) = x^2 + 4x + 20 find the real roots. take your time if you want :)

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
8 0

Answer:

No real roots

x = -2 + 4i, x = -2 - 4i

Step-by-step explanation:

Hello!

We can solve the quadratic by using the Quadratic Formula.

Standard form of a Quadratic: ax^2 + bx + c = 0

Quadratic Equation: x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}

Given our Equation: f(x) = x^2 + 4x + 20

  • a = 1
  • b = 4
  • c = 20

Set the equation to 0 and solve using the formula.

<h3>Solve</h3>
  • x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}
  • x = \frac{-4\pm\sqrt{4^2 - 4(1)(20)}}{2(1)}
  • x = \frac{-4\pm\sqrt{16 - 80}}{2}
  • x = \frac{-4\pm\sqrt{-64}}{2}
  • x = \frac{-4\pm8i}{2}
  • x = -2 + 4i, x = -2 - 4i

There are no real roots to the quadratic.

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