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Illusion [34]
2 years ago
6

If UV ≅ UX and WX=23, what is VW? VW =

Mathematics
1 answer:
expeople1 [14]2 years ago
7 0

Answer: VW= 23

Step-by-step explanation:

Because UV  =  UX the bisector has to split it evenly therefor WX = VW

So the answer is 23!  Does this make sense?

You might be interested in
Can someone please explain expanded form with this number 15,409
Anarel [89]
The expanded form of 15,409 would be 15,000 + 400 + 9.

Your 15 would alone be 15,000. The 409 is turned into zeros.
For 409, take the 9 off of the end and keep it by itself, and then add a zero in replace for the 9, which makes 400. 
The 9 should come in at the last part as it is the last number.

Add them all together and you should get <span>15,000 + 400 + 9.</span>



3 0
3 years ago
Find the cost of erecting a 6 m by 4 m rectangular garden shed that is 2 m high if
Dafna1 [17]

Answer:

2320000

Step-by-step explanation

work out the perimeter first 6+4 times 2= 20

20 time 2m high=40

40 times 58000= 2320000

7 0
3 years ago
Which equation best represents the line?
liubo4ka [24]

Answer:

y = 3x - 1

Step-by-step explanation:

Rise over run, so 3 over 1 = 3. The y-intercept is -1, so b = -1.

6 0
3 years ago
A shipment has 22 products, of which 3 are defective. Three people in turn pick up, each person picks up a product at random (no
Alla [95]

Answer:

Probability of no one picking up a defective product = 571 / 1540

Step-by-step explanation:

Total number of items = 22

non-defective items = 22-3 = 19

Probability of all three picking up non-defective products

= 19/22 * 18/21 * 17/20

= 969/1540

Probability of at least one picking up a defective product

= 1 - 969/1540

= 571/1540

(=0.371, approx.)

6 0
3 years ago
In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home. Give the value of th
astra-53 [7]

Answer:

The value of the standard error for the point estimate is of 0.0392.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.

This means that n = 100, p = \frac{81}{100} = 0.81

Give the value of the standard error for the point estimate.

This is s. So

s = \sqrt{\frac{0.81*0.19}{100}} = 0.0392

The value of the standard error for the point estimate is of 0.0392.

7 0
3 years ago
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