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Scorpion4ik [409]
3 years ago
9

When calculated, the two differences given below are equal.

Mathematics
1 answer:
lidiya [134]3 years ago
4 0
The answer
let be 
A1 = (2x^4-3x^3+2x+4)-(-x^4-3x^3+4x^2+x+3) =
     = 2x^4-3x^3+2x+4 +x^4 +3x^3- 4x^2- x-3
A1= 6x^4 -2x² +x +1
and 
A2= 5x^4-2x^3+3x^2+3x-4-(2x^4-2x^3+7x^2+2x-5)
    = 5x^4-2x^3+3x^2+3x-4-2x^4+2x^3-7x^2-2x+5
A2<span>= 3x^4-4x²+x+1

A1 is not equivalent to A2
so the answer is </span><span>B. False </span>
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A rectangular box is constructed in 3-space with one corner at the origin and other vertices at (1, 0, 0), (0, 4, 0), (0, 0, 2).
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This can be found using the Pythagorean theorem. A drawing can help. Find the length of any face diagonal, then use that length as the leg of a right triangle whose hypotenuse is the space diagonal and whose other leg is the edge length not used in the first calculation.

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Which of the following is not a Pythagorean triple?
Ierofanga [76]

Answer:

  (7, 24, 26)

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<em>Additional comment</em>

For an odd integer n, a triple can be formed as ...

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That is, the following will be Pythagorean triples.

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8 0
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Y= 2x + 6 for x = 0,1,2,3,4
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8 0
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