Answer:
y=8-x or y=9-x or y=243-x (The spot where the 8 is can be any number as long as the number infront of the 0 is still -1)
Step-by-step explanation:
Answer:
<h2><em>
Three to the three fifths power.</em></h2>
Step-by-step explanation:
The given expression is
![\sqrt{3\sqrt[5]{3} }](https://tex.z-dn.net/?f=%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%20%7D)
To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:
![\sqrt[n]{x^{m}}=x^{\frac{m}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%3Dx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)
Applying the property, we have:
![\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%7D%3D%5Csqrt%7B3%283%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%7D%3D%283%283%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
Now, we multiply exponents:

Then, we sum exponents to get the simplest form:
![3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}} \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }](https://tex.z-dn.net/?f=3%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D3%5E%7B%5Cfrac%7B1%7D%7B10%7D%7D%3D3%5E%7B%5Cfrac%7B1%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B10%7D%7D%20%3D3%5E%7B%5Cfrac%7B10%2B2%7D%7B20%7D%7D%3D3%5E%7B%5Cfrac%7B12%7D%7B20%7D%7D%20%20%5C%5C%5Ctherefore%20%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%7D%3D3%5E%7B%5Cfrac%7B3%7D%7B5%7D%20%7D)
Therefore, the right answer is <em>three to the three fifths power.</em>
Answer:
b. the area of a rectangle with side lengths 1.3 and x
Step-by-step explanation:
Answer:
A.77
Step-by-step explanation:
The line makes 180 and one side is 103 so you subtract 103 from 180 to make it equal
Answer:
g(4) = 19
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = x² + 3
g(4) is x = 4
<u>Step 2: Solve</u>
- Substitute: g(4) = 4² + 3
- Evaluate: g(4) = 16 + 3
- Add: g(4) = 19