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2 years ago

Calculate the probability for the following situation, then select the correct answer:

Mathematics

1 answer:

masya89 [10]2 years ago

3 0

The probability is P = 0.135

<h3>How to find the probability?</h3>

First, we need to find the individual probabilities, that are given by the quotient between the number of outcomes that meet the condition and the total number of outcomes.

P(head) = 1/2
P(odd number) = 3/6 (there are 3 odd numbers on the dice)
P(card greater than 6) = 28/52 (28 cards with numbers larger than 6).

The joint probability is given by the product between the individual probabilities, so we get:

P = (1/2)*(3/6)*(28/52) = 0.135

If you want to learn more about probability:

brainly.com/question/25870256

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3 years ago

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mote1985 [20]

Answer:

The answer is:

$\left[\begin{array}{ccc}-29&-16\\14&15\end{array}\right]$

Step-by-step explanation:

(Presuming you wanted to add these)

From the image that is given/shown, this is matrices.

In matrices, the numbers will somewhat correlate with each other!

From what is stated, "Find 3M + 7N"

We must substitute in M and N for the pair of matrices that are given:

M = $\left[\begin{array}{ccc}2&-3\\0&6\\\end{array}\right]$ and N = $\left[\begin{array}{ccc}-5&-1\\2&9\\\end{array}\right]$

You will then be left with:

3 $\left[\begin{array}{ccc}2&-3\\0&6\\\end{array}\right]$ + 7 $\left[\begin{array}{ccc}-5&-1\\2&9\\\end{array}\right]$

when then need to add these together:

1) First Multiply the matrix by 3, you'll get:

$\left[\begin{array}{ccc}6&-9\\0&18\\\end{array}\right] + 7\left[\begin{array}{ccc}-5&-1\\2&9\\\end{array}\right]$

(Each number in the matrix is being multiplied by the values: 3 or 7)

2) Then Multiply the matrix by 7, and you'll get:

$\left[\begin{array}{ccc}6&-9\\0&18\\\end{array}\right] + \left[\begin{array}{ccc}-35&-7\\14&63\\\end{array}\right]$

3) Add the matrices:

$\left[\begin{array}{ccc}6+(-35)&-9+(-7)\\0+(14)&18+(63)\\\end{array}\right]$

6 - 35 = -29

-9 - 7 = -16

0 + 14 = 14

18 + 63 = 81

After solving the matrices, you get:

$\left[\begin{array}{ccc}-29&-16\\14&15\end{array}\right]$

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