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Elis [28]
3 years ago
5

Whats the answer to this

Mathematics
1 answer:
shutvik [7]3 years ago
4 0
9/12 matches to 3/4 For questions like this I like to use apps like Socratic, it shows answers from multiple sites and can solve almost any question.
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Use the Pythagorean Theorem to solve for the missing side length. Round to the nearest tenth if necessary.
Ede4ka [16]

Answer:

B= 6

Step-by-step explanation:

pythagorean theorem formula is a² + b² = c²

so: 8² + b² = 10²

then: 64 + b² = 100

subtract 64 from both sides to get b²= 36

square root 36 and you get 6 for b

answer: B= 6

8 0
3 years ago
the scatter plot shows the relationship between the cost of animal feed and its weight. which option best describes the associat
Ludmilka [50]

Answer: As the weight increases, the price increases

Step-by-step explanation: it’s the only one that actually makes sense

8 0
3 years ago
The 12 boys in the class make up 15% of the class. What is the total number of students in the class?
alina1380 [7]

Answer:

80 students

Step-by-step explanation:

12/80 is 0.15 or 15%

5 0
2 years ago
For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

3 0
3 years ago
 10  points for this                                                                                                            
kow [346]
<span>The range would be all real numbers such that 0 ≤ y ≤ 40.

hope this helps!</span>
3 0
3 years ago
Read 2 more answers
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