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Dafna1 [17]
1 year ago
9

A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the

trip. Each small car can hold 5 people and each large car can hold 7 people. A total of 10 cars were rented which can hold 66 people altogether. Write a system of equations that could be used to determine the number of small cars rented and the number of large cars rented. Define the variables that you use to write the system.
Mathematics
1 answer:
dangina [55]1 year ago
3 0

The system of equations that could be used to determine the number of small cars rented and the number of large cars rented is;

x + y = 10

x + y = 105x + 7y = 66

<h3>Simultaneous equation</h3>

  • Small car = 5 people
  • Large car = 7 people
  • Total cars = 10
  • Total number of people = 66

Let

Number of small cars rented = x

Number of large cars rented = y

x + y = 10

x + y = 105x + 7y = 66

Learn more about simultaneous equation:

brainly.com/question/16863577

#SPJ1

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cricket20 [7]
The answer is b. 2,8 and 3,11
8=3(2)+2
8=6+2
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11=9+2
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3 years ago
I need help on this question!
Romashka [77]
It would be C because if you plug all the x-values in to the equation, it would get the same y values, which would satisfy the equation.
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3 years ago
Tan x is ........ Cos x is ........ Sin x is ..........
fomenos

Answer:

Tan x= 3/4 Cos x= 4/5 Sin x=3/5

Step-by-step explanation:

"soh-cah-toa"

Just an easy way to remember how Sine, Cosine and Tangent work:

Soh...

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3 years ago
Read 2 more answers
Bob Nale is the owner of Nale's Texaco GasTown. Bob would like to estimate the mean number of litres (L) of gasoline sold to his
Fudgin [204]

Answer:

a

  The point estimate of the population mean is  \= x  =  56

b

  The 80% confidence level is  50.57 <  \mu  < 61.43

c

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Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  18

   The  standard deviation is  \sigma  =  18 \ L

   The  sample mean is  \= x  =  56

Generally the point estimate of the population mean is equivalent to the sample mean whose value is  \= x  =  56

Given that the confidence interval is 80% then the level of significance is mathematically represented as

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      \alpha =  20 \%

      \alpha = 0.20

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table

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 Generally the margin of error is mathematically evaluated as

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=>       E =  1.28 * \frac{18 }{\sqrt{18} }

=>       E =  5.43

     Generally the 80% confidence interval is mathematically represented as

    \= x  - E  <  \mu  < \= x  + E

=>    56  - 5.43  <  \mu  < 56  + 5.43

=>   50.57 <  \mu  < 61.43

The  interpretation is that there is  80% confidence that the true population mean lies within the limit

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Answer:

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Step-by-step explanation:

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