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2 years ago

Mhanifa please help! Solve for the unknown in each triangle. Round to the nearest tenth.

Mathematics

1 answer:

Scilla [17]2 years ago

8 0

Answer:

(D)

Use the law of sines:

13 / sin x = 12 / sin 67°
sin x = 13 sin 67° / 12
sin x = 0.997
x = arcsin (0.997)
x = 85.6°

(E)

Find the third angle:

180° - (48° + 61°) = 71°

Use the las of sines:

x / sin 61° = 21 / sin 71°
x = 21 sin 61° / sin 71°
x = 19.4 cm

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What are the awnsers SHOW WORK!! Please

rusak2 [61]

Answer:

Step-by-step explanation:
The rules For fractions: Multiple Denominator to Denominator and Numerator to numerator!

Ok: For number 1

3/5*1/1= 3/5

Number 2

3/4*9/4=27/16= 1 11/16

Number 3

14/21=2/3*33/7=66/21= 3 3/21= 3 1/7

Number 4

6/18*9/42= 1/3*3/14= 3/42= 1/14

Number 5

22/15*45/4= 33/2=16 1/2

Number 6

3/28* 35/6= 105/168= 5/8

Number 7

2/7*35/12=60/84=5/6

Number 8

16/15*21/24=16/15* 7/8=112/120=14/15

Hope It helps!!!!

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1 year ago

-8 - 1/3n ≤ - 25 Please show the equation and steps please

sergey [27]

Answer:
-8 - 1/3n ≤ - 25
solving-n E [51,+oo] , {n|n ≤ 51}
answer-n ≤ 51

Step-by-step explanation:

I hope its help
Brainliest me pls
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3 0

2 years ago

Read 2 more answers

Find the nth term of this quadratic sequence 3, 11, 25, 45, .

Hoochie [10]

The term of the given quadratic sequence is found to be 3n² - n + 1 using the principle of mathematical induction.

Given,

In the question:

The quadratic sequence is :

3, 11, 25, 45, ...

To find the nth term of the quadratic sequence.

Now, According to the question;

The first term of the sequence is 3, the second term is 11, the third term is 25, and the fourth term is 45.

The difference between the first and second terms can be calculated as follows:

11-3 = 8

The difference between the second and third terms can be calculated as follows:

25-11 = 14

The difference between the third and fourth terms can be calculated as follows:

45-25 = 20

The sequence is expressed as follows:

3,3+8,11+11,25+20,...

The difference between consecutive terms expands by 6.

Use the principle of mathematical induction.

6 $(\frac{n(n+1)}{2} )$

= 3n(n+1)

The sequence's nth term can be calculated as follows:

term = 3n(n+1) - 4n + 1

= 3n² - n + 1

Hence, the term of the given quadratic sequence is found to be 3n² - n + 1 using the principle of mathematical induction.

Learn more about Principle of mathematical induction at:

brainly.com/question/29222282

#SPJ1

6 0

1 year ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial: