Answer:
1. z = 128
2. x = 4.2
3. c = 10
4. w = 100
5. a = 95.2
Step-by-step explanation:
1. Solve for z:
z/16 = 8
Multiply both sides of z/16 = 8 by 16:
(16 z)/16 = 16×8
(16 z)/16 = 16/16×z = z:
z = 16×8
16×8 = 128:
Answer: z = 128
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2. Solve for x:
3.5 x = 14.7
Divide both sides of 3.5 x = 14.7 by 3.5:
(3.5 x)/3.5 = 14.7/3.5
3.5/3.5 = 1:
x = 14.7/3.5
14.7/3.5 = 4.2:
Answer: x = 4.2
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3. Solve for c:
32 = 3.2 c
32 = 3.2 c is equivalent to 3.2 c = 32:
3.2 c = 32
Divide both sides of 3.2 c = 32 by 3.2:
(3.2 c)/3.2 = 32/3.2
3.2/3.2 = 1:
c = 32/3.2
32/3.2 = 10:
Answer: c = 10
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4. Solve for w:
(2 w)/5 = 40
Multiply both sides of (2 w)/5 = 40 by 5/2:
(5×2 w)/(2×5) = 5/2×40
5/2×2/5 = (5×2)/(2×5):
(5×2)/(2×5) w = 5/2×40
5/2×40 = (5×40)/2:
(5×2 w)/(2×5) = (5×40)/2
(5×2 w)/(2×5) = (2×5)/(2×5)×w = w:
w = (5×40)/2
2 | 2 | 0
| 4 | 0
- | 4 |
| | 0
| - | 0
| | 0:
w = 5×20
5×20 = 100:
Answer: w = 100
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5. Solve for a:
a/14 = 6.8
Multiply both sides of a/14 = 6.8 by 14:
(14 a)/14 = 14×6.8
(14 a)/14 = 14/14×a = a:
a = 14×6.8
14×6.8 = 95.2:
Answer: a = 95.2
Answer:
The function touches the damping factor
at x=
and x=
The x-intercept of f(x) is
at x=
Step-by-step explanation:
Given function is f(x)=
and damping factor as y=
and y=
To find when function touches the damping factor:
For f(x)=
and y=
Equating the both the equation,


x=
For f(x)=
and y=
Equating the both the equation,


x=
Therefore, The function touches the damping factor x=
and x=
To find x-intercept of f(x):
For x-intercept, y=0
f(x)=
y=

Hence,
is always greater than zero.
Therefore,
x=
Thus,
The x-intercept of f(x) is at x=
If (-5) = x then the anwser should be
-234
The answer is,

Also equivalent to about, 0.185188.
The nearest tenth is still zero. Reason being you have to start from the right, and once you round the far most 9 to the zero it turns to a one which is too small of a number to round up.