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2 years ago

Ask me questions because I am bored

Mathematics

1 answer:

lana66690 [7]2 years ago

5 0

Answer:

how are you?

Step-by-step explanation:

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20) The volume of a cone is 1871 cubic feet. If the height of the cone is 6 ft, what is the radius of the cone? (V =

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Step-by-step explanation:

Good Luck and I hope you do well :)

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2 years ago

What rule changes the input to output numbers?

Deffense [45]

Each pair of numbers in the table is related by the same function rule. That rule is: multiple each input number value by 3 to find each output number value. You can use a rule like this to find other values for this function, too

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3 years ago

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If cos theta = 1/4 and 0 degrees, find tan theta

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2 years ago

Julia paints 2/6 of a wall in her room white. She paints more of the wall green than white. What fraction could show the part of

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3 years ago

The caffeine content (in mg) was examined for a random sample of 50 cups of black coffee dispensed by a new machine. The mean an

Genrish500 [490]

Answer:

We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 mg .

Step-by-step explanation:

Given -

The sample size is large then we can use central limit theorem

n = 50 ,

Standard deviation $(\sigma)$ = 7.1

Mean $\overline{(y)}$ = 110

$\alpha =$ 1 - confidence interval = 1 - .98 = .02

$z_{\frac{\alpha}{2}}$ = 2.33

98% confidence interval for the mean caffeine content for cups dispensed by the machine = $\overline{(y)}\pm z_{\frac{\alpha}{2}}\frac{\sigma}\sqrt{n}$

= $110\pm z_{.01}\frac{7.1}\sqrt{50}$

= $110\pm 2.33\frac{7.1}\sqrt{50}$

First we take + sign

$110 + 2.33\frac{7.1}\sqrt{50}$ = 112.34

now we take - sign

$110 - 2.33\frac{7.1}\sqrt{50}$ = 107.66

We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 .

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3 years ago