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ra1l [238]
1 year ago
6

Find the remainder when f(x)=−2x3+x2−4x+1 is divided by x+3.

Mathematics
1 answer:
harina [27]1 year ago
4 0

The remainder when f(x)=−2x3+x2−4x+1 is divided by x+3. is 76

<h3>How to determine the remainder?</h3>

The function is given as:

f(x)=−2x3+x2−4x+1 is divided by x+3.

Set the divisor to 0

x + 3 = 0

Solve for x

x = -3

Calculate f(-3)

f(-3)=−2(-3)^3+(-3)^2 − 4(-3) + 1

Evaluate the expression

f(-3)= 76

Hence, the remainder when f(x)=−2x3+x2−4x+1 is divided by x+3. is 76

Read more about remainder theorem at:

brainly.com/question/13328536

#SPJ1

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A triangle has side lengths of 13, 9, and 5. Is the triangle a right triangle? Explain.
valentina_108 [34]

Answer: This triangle is <u>not</u> a right triangle

Step-by-step explanation:

In a right triangle, the hypotenuse(c) is always the longest side and a and b are the shorter sides.  Thus, 5^2+9^2=13^2.  Simplify this to get 25+81=169, then 106=169.  Because 106 does <u>not</u> equal 169, it is not a right triangle.

<em>Hope it helps <3</em>

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2 years ago
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What other information do you need in order to prove the triangles congruent using the SAS congruence postulate
iren [92.7K]

AC is perpendicular to BD.

<h3>Further explanation</h3>
  • We observe that both the ABC triangle and the ADC triangle have the same AC side length. Therefore we know that \boxed{ \ \overline{AC} \cong \overline{AC} \ } is reflexive.
  • The length of the base of the triangle is the same, i.e., \boxed{ \ \overline{BC} = \overline{CD} \ }.
  • In order to prove the triangles congruent using the SAS congruence postulate, we need the other information, namely \boxed{ \ AC \bot BD \ }. Thus we get ∠ACB = ∠ACD = 90°.

Conclusions for the SAS Congruent Postulate from this problem:

  • \boxed{ \ \overline{BC} = \overline{CD} \ }
  • ∠ACB = ∠ACD
  • \boxed{ \ \overline{AC} = \overline{AC} \ }

- - - - - - - - - -

The following is not other or additional information along with the reasons.

  • ∠CBA = ∠CDA no, because that is AAS with ∠ACB = ∠ACD and \boxed{ \ \overline{AC} \cong \overline{AC} \ }
  • ∠BAC = ∠DAC no, because that is ASA with \boxed{ \ \overline{AC} \cong \overline{AC} \ } and ∠ACB = ∠ACD.
  • \boxed{ \ \overline{BC} = \overline{CD} \ } no, because already marked.

- - - - - - - - - -

Notes

  • The SAS (Side-Angle-Side) postulate for the congruent triangles: two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle; the included angle properly represents the angle formed by two sides.
  • The ASA (Angle-Side-Angle) postulate for the congruent triangles: two angles and the included side of one triangle are congruent to two angles and the included side of another triangle; the included side properly represents the side between the vertices of the two angles.  
  • The SSS (Side-Side-Side) postulate for the congruent triangles: all three sides in one triangle are congruent to the corresponding sides within the other.
  • The AAS (Angle-Angle-Side) postulate for the congruent triangles: two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.  
<h3>Learn more</h3>
  1. Which shows two triangles that are congruent by ASA?  brainly.com/question/8876876  
  2. Which shows two triangles that are congruent by AAS brainly.com/question/3767125
  3. About vertical and supplementary angles brainly.com/question/13096411  
9 0
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Find the area of the circle. Round your answer to the nearest hundredth.<br> 3 in.
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Answer:

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Step-by-step explanation:

The area of a circle is dependent on only one variable:  the radius:

A = πr²

If the radius is 3 inches, as you seem to indicate, then:

A = π(3 in)² = 9π in²  = 28.27 in²

7 0
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