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s344n2d4d5 [400]
2 years ago
13

Identify which property you would use first to solve the following equation.

Mathematics
1 answer:
IceJOKER [234]2 years ago
5 0

Answer:

Distributive property

Step-by-step explanation:

In order to solve this equation we first need to distribute 3 into 2y+5, we use the distributive property to do this.

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I need help please and thank you
Sphinxa [80]
The answer is I believe: 21
8 0
3 years ago
If the zeros of f(x) are x=-1 and x=2, then the zeros of f(x/2) are
RSB [31]

Answer:

E (-2, 4).

Step-by-step explanation:

(x/2 + 1)(x/2 - 2) = 0

x/2 = -1,  x/2 = 2

x = -2, 4.

The roots will be 2 times the roots of f(x).

6 0
3 years ago
Read 2 more answers
Find the value of the expression. <br> pm + 4 <br> for m = 4 and p = 4
kvv77 [185]

m = 4, p = 4

Note that when two variables are placed directly next to each other, you are multiplying

plug in 4 for both m and p

(4)(4) + 4

Multiply

4 x 4 = 16

Add

16 + 4 = 20

20 is your answer

hope this helps

3 0
3 years ago
How do you write a polynomial function for this graph?
expeople1 [14]

first off, let's notice the graph touches the x-axis at -1 and 3, namely, those are the zeros/solutions/roots of the polynomial and therefore, the factors come from those points.

now, at -1, the graph doesn't cross the x-axis, instead it <u>simply bounces off</u> of it, that means the zero of x = -1, has an even multiplicity, could be 4 or 2 or 6, but let's go with 2.

at x = 3, the graph does cross the x-axis, meaning it has an odd multiplicity, could be 3 or 1, or 7 or 9, but let's use 1.


\bf \begin{cases} x=-1\implies &x+1=0\\ x=3\implies &x-3=0 \end{cases}~\hspace{5em}\stackrel{\textit{even multiplicity}}{(x+1)^2}\qquad \stackrel{\textit{odd multiplicity}}{(x-3)^1}=\stackrel{y}{0} \\\\\\ (x^2+2x+1)(x-3)=y\implies x^3+2x^2+x-3x^2-6x-3=y \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^3-x^2-5x-3=y~\hfill

5 0
3 years ago
Read 2 more answers
Simplify. x^3 ÷ x^5​
fomenos

Answer:

x^-2

Step-by-step explanation:

(x*x*x)/(x*x*x*x*x)

1/x*x

1/x^2

x^-2

3 0
3 years ago
Read 2 more answers
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