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sleet_krkn [62]
2 years ago
10

If the zeros of f(x) are x=-1 and x=2, then the zeros of f(x/2) are

Mathematics
2 answers:
7nadin3 [17]2 years ago
8 0

Answer:

\Large \boxed{\mathrm{E. \ -2, \ 4}}

Step-by-step explanation:

The zeros of f(x/2) will double the zeros of f(x).

x = -1 × 2 = -2

x = 2 × 2 = 4

RSB [31]2 years ago
6 0

Answer:

E (-2, 4).

Step-by-step explanation:

(x/2 + 1)(x/2 - 2) = 0

x/2 = -1,  x/2 = 2

x = -2, 4.

The roots will be 2 times the roots of f(x).

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Answer:

0

Step-by-step explanation:

-4|2-3|+2|-3+1|

-4|-1|+2|-2|

-4(1)+2(2)

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0

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3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
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Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

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Hope this helps you.

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Someone help me please, this topic is based on slopes.
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Answer:

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The run is 5 and the rise is 1

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