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SpyIntel [72]
2 years ago
8

For an air bag to work, it has to inflate full of nitrogen incredibly fast-within to

Physics
1 answer:
Lunna [17]2 years ago
8 0

5.8 moles of nitrogen gas are needed to pressurize the air bag.

<h3>What's the expression of Ideal gas equation?</h3>
  • Ideal gas equation is PV=nRT
  • P= pressure, V = volume, n= no. of moles of gas, R= universal gas constant, T = temperature of the gas

<h3>What's the no. of moles of nitrogen present in a 60L air bag at 2.37 atm pressure and 25°C temperature?</h3>
  • P= 2.37 atm, V = 60L, R= 0.0821 L-atm/mol-K, T = 25°C = 298K
  • n= PV/RT

= (2.37×60)/(0.0821×298)

= 5.8 moles

Thus, we can conclude that 5.8 moles of nitrogen gas are needed to pressurize the air bag.

Learn more about the ideal gas here:

brainly.com/question/20348074

#SPJ1

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Substituting, we find
p=1.0 \cdot 10^5 Pa + (1000 kg/m^3)(9.81 m/s^2)(4267 m)=4.20 \cdot 10^7 Pa
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An airliner arrives at the terminal, and its engines are shut off. The rotor of one of the engines has an initial clockwise angu
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(a) 1200 rad/s

The angular acceleration of the rotor is given by:

\alpha = \frac{\omega_f - \omega_i}{t}

where we have

\alpha = -80.0 rad/s^2 is the angular acceleration (negative since the rotor is slowing down)

\omega_f is the final angular speed

\omega_i = 2000 rad/s is the initial angular speed

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Solving for \omega_f, we find the final angular speed after 10.0 s:

\omega_f = \omega_i + \alpha t = 2000 rad/s + (-80.0 rad/s^2)(10.0 s)=1200 rad/s

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We can calculate the time needed for the rotor to come to rest, by using again the same formula:

\alpha = \frac{\omega_f - \omega_i}{t}

If we re-arrange it for t, we get:

t = \frac{\omega_f - \omega_i}{\alpha}

where here we have

\omega_i = 2000 rad/s is the initial angular speed

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Solving the equation,

t=\frac{0-2000 rad/s}{-80.0 rad/s^2}=25 s

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A solid non-conducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a radius r (r &lt;
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Answer:  

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