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Mama L [17]
3 years ago
15

What disadvantage does floating buoys have when it comes to converting wave energy to electrical energy? A) They generate only m

inimum amounts of electricity. B) They pose a risk to migrating whales in the ocean. C) They are easily degraded by the salt water. D) The turbulent ocean often breaks these buoys. Grade Results got me messed up my dudes.
Physics
1 answer:
arsen [322]3 years ago
6 0

Answer:

B

Explanation:

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I need help quickly pls
sukhopar [10]

Answer:

Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:

Explanation:

4 0
3 years ago
See attachment for question
zloy xaker [14]

The Mercury's mass for the given acceleration due to gravity is 0.3152 x 10²⁴ kg.

The ratio of the calculated and accepted value of the Mercury's mass is 0.95.

<h3>What is mass?</h3>

Mass is the amount of matter present in the object.

The mass of the object is always constant, anywhere it is on the Earth or Moon or any other planet.

Given is the acceleration due to gravity of Mercury planet at North pole is g = 3.698 m/s² and the radius of Mercury planet is 2440 km.

The acceleration due to gravity is related with mass as

g = GM/R²

Substitute the values, we have

3.698 = 6.67 x 10⁻¹¹ x M/(2440 x1000)³

M = 2.2016 x 10¹³ /  6.67 x 10⁻¹¹

M = 0.3152 x 10²⁴ kg

Thus, the mercury's mass is  0.3152 x 10²⁴ kg.

(b) Accepted value of Mercury's mass is 3.301 x 10²³ kg

Ratio of the value of mass calculated and accepted is

Mcalc/M accep =  0.3152 x 10²⁴ kg / 3.301 x 10²³ kg

                          = 0.95

Thus, the ratio is 0.95

Learn more about mass.

brainly.com/question/19694949

#SPJ1

8 0
1 year ago
what is the power of an electrical device which operates with a current of 12.4 A and a potential difference of 12 V​
jek_recluse [69]

148.8 Watts

Explanation:

P = VI

= (12 V)(12.4 A)

= 148.8 Watts

3 0
2 years ago
Consider blood (density 1025 kg/m3) flowing through an artery with circular cross section that looks like this: Ignore viscosity
Klio2033 [76]

The given question is incomplete. The complete question is attached with an image below.

Explanation:

Mass flow rate through region A will be calculated as follows.

Rate = \rho \times A \times \mu

       = \rho \times \pi \times R^{2} \times \mu

       = 1025 \times 3.14 \times (0.5 \times 10^{-2})^{2} \times 30 \times 10^{-2}

       = 24138.75 \times 10^{6} kg/s

Therefore, we can conclude that the mass flow rate through region A is 24138.75 \times 10^{6} kg/s.

8 0
3 years ago
What would be the answer pls answer ASAP
ELEN [110]
I would say D. 22.25 ml because there’s a curve
3 0
2 years ago
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